Answer:
The interior angles are 70°,65°,80°,155° and 170°
Step-by-step explanation:
step 1
Find the sum of the interior angles of the pentagon
The sum is equal to
S=(n-2)*180°
where
n is the number of sides of polygon
n=5 (pentagon)
substitute
S=(5-2)*180°=540°
step 2
Find the value of x
Sum the given angles and equate to 540
x+(x-5)+(x+10)+(2x+15)+(2x+30)=540°
7x+50=540°
7x=490°
x=70°
step 3
Find all the angles
x=70°
(x-5)=(70-5)=65°
(x+10)=(70+10)=80°
(2x+15)=(2*70+15)=155°
(2x+30)=(2*70+30)=170°
Using the left or right side of triangle, you can conclude that the midsegment will divide the triangle in both midlines of the sides. This means the length of the line would be half of the line below it. The equation would be:
47/4x+2= 94/ 4x+44
4x+44/ 4x+2 = 94/47
4x+ 44 / 4x+2 =2
4x+44 = 2(4x+2)
4x+44 = 8x+4
4x-8x= 4-44
-4x= -40
x= 10
Then the length of midline would be:
4x+2= 4(10)+2= 42
Use PEMDAS.
Compute in order of parentheses, exponents, multiplication, division, addition, subtraction.