Please show work on how to simplify this 1/x^-3/6 Thank you in advance
1 answer:
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Answer:
The system of hypothesis for this case are:
Null hypothesis:
Alternative hypothesis:
A type of error I for this case would be reject the null hypothesis that the true mean is equal than 150 when actually is not true.
Step-by-step explanation:
Previous concepts
A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".
The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".
The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".
Type I error, also known as a “false positive” is the error of rejecting a null hypothesis when it is actually true. Can be interpreted as the error of no reject an alternative hypothesis when the results can be attributed not to the reality.
Type II error, also known as a "false negative" is the error of not rejecting a null hypothesis when the alternative hypothesis is the true. Can be interpreted as the error of failing to accept an alternative hypothesis when we don't have enough statistical power.
Solution to the problem
The system of hypothesis for this case are:
Null hypothesis:
Alternative hypothesis:
A type of error I for this case would be reject the null hypothesis that the true mean is equal than 150 when actually is not true.
Answer:
¿Cuántos DVD de cada tipo debe fabricar y vender para que la utilidad sea máxima?
Se debe fabricar y vender 20 DVD del modelo A y 30 DVD del modelo B. La utilidad máxima es de de S/. 1 800
Step-by-step explanation:
x : Número de DVD del modelo A
y : Número de DVD del modelo B.
MODELO A MODELO B TOTAL
Cantidad de caucho 1x 1x 50 kg.
Horas de mano de obra 1x 2x 80 horas
U : Utilidad mensual.
La función objetivo, que se debe maximizar, es:
U=30 + 40y
x+ y
x + 2y
x
y
Las coordenadas de los vértices de la región factibles son:
A (0, 0) B (50, 0) C (20, 30) D(0, 40)
Entonces, se evalúa la función objetivo en cada punto:
U (0, 0) = 30 (0) + 40 (0) = 0
U (50, 0) = 30 (50) + 40(0) = 1500
U (90, 0) = 30 (20) + 40 (30) = 1800
U (0, 40) = 30 (0) + 40 (40) =1600
Por consiguiente U tiene un valor máximo en C , en donde: x =20 , y = 30 .
Se debe fabricar y vender 20 DVD del modelo A y 30 DVD del modelo B. La utilidad máxima es de de S/. 1 800.
30 x 40 y
s.a.
x 0 (3)
y 0 (4)
Answer:
a. (2 - x, -4 - 1/2y)
Step-by-step explanation:
Simplify to get the answer.