Since c=15 and d=3, we replace the c and d variables with 15 and 3.
0.5x15-1.7x3
0.5x15=7.5
1.7x3=5.1
Now subtract.
7.5-5.1=2.4
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hope it helps
0.32 cents for each unit because if you divide 7.68 by 24 it is 0.32
Answer:
H0: μ = 5 versus Ha: μ < 5.
Step-by-step explanation:
Given:
μ = true average radioactivity level(picocuries per liter)
5 pCi/L = dividing line between safe and unsafe water
The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.
A type I error, is an error where the null hypothesis, H0 is rejected when it is true.
We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.
Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.
There will be 42 in each row with 2 left over
Answer:
y = -3x + 4
Step-by-step explanation:
I graphed the equation and the point given on the graph below. The other line is the equation that is parallel.
If this answer is correct, please make me Brainliest!
