I believe this is the way to solve it.
22 - 2 = 20
20 is 90.9% of 22
So the probability of choosing a student with a sibling at random should be 90.9% (or you can round up to 91%)
I hope this helps :)
10 times 3 is 3000...so the number 3 would have to be in the thousandths place...for e.g. 93,750
Answer:
1st picture: (0,4)
The lines intersect at point (0,4).
2nd picture: Graph D
2x ≥ y - 1
2x - 5y ≤ 10
Set these inequalities up in standard form.
y ≤ 2x + 1
-5y ≤ 10 - 2x → y ≥ -2 + 2/5x → y ≥ 2/5x - 2
When you divide by a negative number, you switch the inequality sign.
Now you have:
y ≤ 2x + 1
y ≥ 2/5x - 2
Looking at the graphs, you first want to find the lines that intersect the y-axis at (0, 1) and (0, -2).
In this case, it is all of them.
Next, you would look at the shaded regions.
The first inequality says the values are less than or equal to. So you look for a shaded region below a line. The second inequality says the values are greater than or equal to. So you look for a shaded region above a line.
That would mean Graph B or D.
Then you look at the specific lines. You can see that the lower line is y ≥ 2/5x - 2. You need a shaded region above this line. You can see the above line is y ≤ 2x + 1. You need a shaded region below this line. That is Graph D.
Answer:
x = 7.55
Step-by-step explanation:
We can use the Pythagorean theorem to solve
a^2 +b^2 = c^2
where a and b are the legs and c is the hypotenuse
a^2 +8^2 = 11^2
x^2 +64 = 121
Subtract 64 from each side
x^2 +64-64 = 121-64
x^2 =57
Take the square root of each side
sqrt(x^2) = sqrt(57)
x = 7.549834435
To the nearest hundredth
x = 7.55
If you subtract 25 from 12 you will get 13 cents. So you will get back 1 dime and 3 pennies.
I hope this helped you :)
