We have that
<span>We will analyze each case to verify the answer
see the attached figure
</span>Point A) 7 cans and 140 bottles------------> (x,y)=(7,140)----> is not solution
Point B) 12 cans and 40 bottles------------> (x,y)=(12,40)----> is not solution
Point C) 8 cans and 120 bottles------------> (x,y)=(8,120)----> is a solution
Point D) 9 cans and 70 bottles------------> (x,y)=(9,70)-------> is a solution
the answer is
the solutions are
<span>
8 cans and 120 bottles9 cans and 70 bottles</span>
Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
Answer:
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
you take the positive value for it
f(-3) = |2×(-3)+1|+5 ➡ |-6+1| + 5 ➡ |-5|+5 = 5+5