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Nina [5.8K]
2 years ago
5

Help me please quickly ​

Mathematics
1 answer:
Elis [28]2 years ago
5 0

Answer:

Step-by-step explanation:

1.   9

2. 32

3. 813

4. 264

5. 169

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20/25 as a decimal is 0.8
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A number cube with the numbers 1 through 6 is rolled. What is the probability of the number cube showing a 4 or a number less th
Sonja [21]

Answer:

Step-by-step explanation:

The probability is

P

(

A

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=

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3

Explanation:

To calculate the probability you have to count the number of all possible results

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Ω

|

and the number of results that fulfill the given condition

|

A

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.

In this case

Ω

=

{

1

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2

,

3

,

4

,

5

,

6

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Thereare 6 possible result of a dice toss. So

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A

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{

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- those are the only numbers divisible by

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A

|

=

2

.

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|

A

|

by

|

Ω

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.

P

(

A

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=

|

A

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|

Ω

|

=

2

6

=

1

3

Note The probability is never larger than

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4 0
3 years ago
Read 2 more answers
Tim cut 2.3-foot length of pipe from a pipe that was 4.1 feet long.How long is the remaining piece of pipe
Elena L [17]
1.3 feet
~~~~~~
4.1
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Identify the slope as positive, negative, zero or undefined
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2 years ago
For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
ICE Princess25 [194]

Answer:

Part a) The area of the figure is \frac{9}{2}(4+\pi )\ cm^{2}

Part b) The perimeter of the figure is 3(2+2\sqrt{2}+ \pi)\ cm

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

AB=6\ cm, BC=6\ cm

The area of the half square ABC is equal to find the area of triangle ABC

so

A1=\frac{1}{2}*6*6=18\ cm^{2}

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

A2=\pi r^{2}/2

we have that

r=6/2=3\ cm

substitute

A2=\pi (3)^{2}/2

A2=(9/2) \pi\ cm^{2}

The area of the figure is equal to

18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

P=AB+AC+length\ CB

we have

AB=6\ cm

Applying Pythagoras theorem

AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm

Remember that

the circumference of a semicircle is equal to

C=\frac{1}{2}2\pi r=\pi r

r=6/2=3\ cm

C=\pi(3)

C=3 \pi\ cm

The perimeter of the figure is equal to

P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm

Simplify

P=3(2+2\sqrt{2}+ \pi)\ cm

5 0
3 years ago
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