Answer:
Given 7b²-21b-273=7, the solutions are x1 = 8 and x2 = -5.
Step-by-step explanation:
Given 7b²-21b-273=7, first you need to equal zero. So
7b²-21b-273-7=0 ⇒ 7b²-21b-280 = 0
The secon step is to find the solutions applying Bhaskara´s formula x = (-b ± √(b²-4×a×c))/2×a
Where a=7, b= -21 and c= -280
After you identified each term, you have to replace it on the formula so....
x = (21 ± √(21² - 4×7×(-280)))/2×7 ⇒ x = (21 ± √(441 + 7840))/14 ⇒ x = (21 ± √8281)/14
Then you will obtain two values for x, called x1 = 8 and x2=-5.
Answer:
v = -2.5
Step-by-step explanation:
9(9-2v) = -12(v-8)
81−18v= −12v+96
So move -18v to the other side and change the sign. Same to 96.
81-96 = -12v + 18v
-15 = 6v
v = -2.5
Solution
Given , Graph of f(x) = x^4 - x^2
and , Graph of g(x) = x^4 - x^2 - 2
when graph of f(x) shifted to 2 units down then
the new graph produced is of g(x)
g(x) = x^4 - x^2 - 2
when graph of f(x) shifted to 2 units downward
then g(x) = x^4 - x^2 - 2
783 divided by 18 equal 43.5
