<u>Answer:</u>
<u>(6x^(3)+11x^(2)-19x+5)-:-(3x-2)</u>
<u>Step-by-step explanation:</u>
for some reason it showed that but yeah hope this helps!
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2 answers:
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Answer:
The correct option is A.
Step-by-step explanation:
The given number is
Where 5 is dividend and 11 is divisor.
Since dividend is less than divisor we add a decimal place and the first zero. Notice the decimal point which has appeared on the answer line and by the dividend. It does not appear anywhere else.
Now the dividend is 50. Divide the number by divisor.
Subtract 44 from 50.
Therefore remainder is 6. Place a zero after 6.
Now the new dividend is 60. Divide the number by divisor.
Subtract 55 from 60.
Therefore remainder is 5.
Therefore option A is correct.
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π → C = π - (A + B)
→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))
→ sin C = sin (A + B) cos C = - cos(A + B)
Use the following Sum to Product Identity:
sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]
cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]
Use the following Double Angle Identity:
sin 2A = 2 sin A · cos A
<u>Proof LHS → RHS</u>
LHS: (sin 2A + sin 2B) + sin 2C
LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C
