The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
Read more about inverse functions at:
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Answer:
6327
Step-by-step explanation:
2109 bpm. you want to know how many times in minutes
Well all you do is 2109*3=6327
Y=1.5x+2 because the rate of change is 1.5 and the y intercept is 2
Answer:
6x+20
c.
Step-by-step explanation:
If f(x)=6x+2 and you are asked to find f(x+3), then you just replace all the x's in f(x)=6x+2 with (x+3).
Doing this gives you:
f(x)=6x+2 with new input (x+3) in place of out input (x)
f(x+3)=6(x+3)+2
f(x+3)=6x+18+2
f(x+3)=6x+20
