Express 28% as a (a) fraction in its lowest terins,

Find the midpoint of the segment that has endpoints at (a+b, a-b) and (a, b).

Hunter-Best [27]

Answer:

((2a+b)/2 , a/2)

Step-by-step explanation:

The midpoint is the mean/average of both the x and y values.

Our x values are a+b and a

Our y values are a-b and b

The midpoint x value is (a+b + a ) /2 = (2a + b)/2

The midpoint y value is (a-b + b) /2 = (a)/2

The midpoint combines these two values to get ((2a+b)/2 , a/2) as our midpoint

5 0

3 years ago

Evaluate the line integral, where c is the given curve. c y3 ds,

postnew [5]

Parameterizing $\mathcal C$ by

$\mathbf r(t)=(t^3,t)$

with $0\le t\le2$ , we have

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt=\sqrt{(3t^2)^2+1^2}\,\mathrm dt=\sqrt{9t^4+1}\,\mathrm dt$

So

$\displaystyle\int_{\mathcal C}y^3\,\mathrm ds=\int_{t=0}^{t=2}t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_0^236t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_{u=1}^{u=145}\sqrt u\,\mathrm du$
$=\dfrac{145^{3/2}-1}{54}$

5 0

3 years ago

Translate Each sentence into an equation!!!

Amanda [17]

20+2N=52
now subtract 20 from each side, to get 2N alone
2N=32
now divide each side by 2
N=16

6 0

3 years ago

The school that Michael goes to is selling tickets to a dance. On the first day of ticket sales the school sold 3 staff tickets

Minchanka [31]

The price of a staff ticket and the price of a student ticket is $8 and $14

Given:

Day 1:

Number of staff tickets sold = 3

Number of students tickets sold = 1

Total revenue day 1 = $38

Day 2:

Number of staff tickets sold = 3

Number of students tickets sold = 2

Total revenue day 2 = $52

let

cost of staff tickets = x

cost of students tickets = y

The equation:

3x + y = 38 (1)

3x + y = 38 (1)3x + 2y = 52 (2)

subtract (1) from (2)

2y - y = 52 - 38

y = 14

substitute y = 14 into (1)

3x + y = 38 (1)

3x + 14 = 38

3x = 38 - 14

3x = 24

x = 24/3

x = 8

Therefore,

cost of staff tickets = x

= $8

cost of students tickets = y

= $14