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rosijanka [135]
2 years ago
5

Solve for x

{3x+13}=2x-3" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
ivanzaharov [21]2 years ago
6 0

Answer:

x=13

Step-by-step explanation:

Allushta [10]2 years ago
4 0
I believe that x actually equals to 4
x=4
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Madison created two functions.
Degger [83]
Madison created two functions.For Function A, the value of y is two less than four times the value of x. 

The table below represents Function B.
-3,-9
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In comparing the rates of change, which statement about Function A and Function B is true?

A.

Function A and Function B have the same rate of change.
B.

Function A has a greater rate of change than Function B has.
C.

Function A and Function B both have negative rates of change.
D.

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C is correct
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3 years ago
Read 2 more answers
What are the zeros of the function below? Check all that apply.
nordsb [41]

F, A.

-3, 1

use a graphing calc

or do

x+3 = 0 or x-1 = 0 to get x = -3 or x = 1


8 0
3 years ago
How far away from home was she ?
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6 0
3 years ago
Y''+Y'+Y=1<br> solve ordinary differential equation
taurus [48]

Answer:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

Step-by-step explanation:

y" + y' + y = 1

This is a second order nonhomogenous differential equation with constant coefficients.

First, find the roots of the complementary solution.

y" + y' + y = 0

r² + r + 1 = 0

r = [ -1 ± √(1² − 4(1)(1)) ] / 2(1)

r = [ -1 ± √(1 − 4) ] / 2

r = -1/2 ± i√3/2

These roots are complex, so the complementary solution is:

y = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t)

Next, assume the particular solution has the form of the right hand side of the differential equation.  In this case, a constant.

y = c

Plug this into the differential equation and use undetermined coefficients to solve:

y" + y' + y = 1

0 + 0 + c = 1

c = 1

So the total solution is:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

To solve for c₁ and c₂, you need to be given initial conditions.

5 0
3 years ago
What is the length of in the rectangular prism? Round to the nearest tenth of a centimeter. A.
BaLLatris [955]
Can you explane it a little more.
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3 years ago
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