Madison created two functions.For Function A, the value of y is two less than four times the value of x.
The table below represents Function B.
-3,-9
-1,5
1,-1
3,3
In comparing the rates of change, which statement about Function A and Function B is true?
A.
Function A and Function B have the same rate of change.
B.
Function A has a greater rate of change than Function B has.
C.
Function A and Function B both have negative rates of change.
D.
Function A has a negative rate of change and Function B has a positive rate of change.
C is correct
F, A.
-3, 1
use a graphing calc
or do
x+3 = 0 or x-1 = 0 to get x = -3 or x = 1
Approx. 5 miles I would say give or take the 1/2 mile shortcut by taking a straight path back to the house. I don't know if you need an exact distance but I hope this helps.
Answer:
y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1
Step-by-step explanation:
y" + y' + y = 1
This is a second order nonhomogenous differential equation with constant coefficients.
First, find the roots of the complementary solution.
y" + y' + y = 0
r² + r + 1 = 0
r = [ -1 ± √(1² − 4(1)(1)) ] / 2(1)
r = [ -1 ± √(1 − 4) ] / 2
r = -1/2 ± i√3/2
These roots are complex, so the complementary solution is:
y = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t)
Next, assume the particular solution has the form of the right hand side of the differential equation. In this case, a constant.
y = c
Plug this into the differential equation and use undetermined coefficients to solve:
y" + y' + y = 1
0 + 0 + c = 1
c = 1
So the total solution is:
y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1
To solve for c₁ and c₂, you need to be given initial conditions.
Can you explane it a little more.
