Answer:
electrophile is pe do file
Explanation:
elecricity = needing a professor= creepy profesor= pe edo
Answer:
The number of oxygen in 7.9 × 10⁻¹ moles of CO₂ is 9.5116 × 10²³ atoms of oxygen
Explanation:
The given parameters are;
The number of moles of CO₂ = 7.9 × 10⁻¹ moles
The number of molecules of CO₂ in one mole of CO₂ = 6.02 × 10²³
The number of molecules, , of CO₂ in 7.9 × 10⁻¹ moles is given as follows;
= 7.9 × 10⁻¹ × 6.02 × 10²³ ≈ 4.76 × 10²³ molecules
The number of atoms of oxygen in one molecule of CO₂ = 2 oxygen atoms
Therefore;
The number of oxygen in 7.9 × 10⁻¹ moles of CO₂ = 2 × 4.76 × 10²³ ≈ 9.5116 × 10²³
The number of oxygen in 7.9 × 10⁻¹ moles of CO₂ ≈ 9.5116 × 10²³ atoms of oxygen.
Answer:
5.20 grams of Br₂
Explanation:
From our previous knowledge;
We understand that:
The number of moles of a given element = mass of the element divided by its molar mass.
Mathematically:
From the given information, let's assume that the 0.065 moles of liquid -bromine partake in the reaction.
From the periodic table, the molar mass of Bromine is = 79.9 g/mol
As such, the mass of liquid that partakes is calculated as:
0.065 mol = mass/ 79.9 g/mol
mass = 0.065 mol × 79.9 g/mol
mass of liquid that partakes in the reaction = 5.20 grams of Br₂
The answers are the following:
1. <span>1.4 x 10^11 kJ/mol
2. </span><span>9.0 × 10^6 kJ
Therefor I conclude that your answers are correct. </span>