The question is incomplete, here is the complete question:
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide:
In the second step, acetylene, carbon dioxide and water react to form acrylic acid:
Write the net chemical equation for the production of acrylic acid from calcium carbide, water and carbon dioxide. Be sure your equation is balanced.
<u>Answer:</u> The net chemical equation is written below.
<u>Explanation:</u>
The intermediate balanced chemical reaction are:
(1)
( × 6 )
(2)
To omit acetylene from the net chemical reaction, we multiply Equation (1) by 6.
<u>Equation 1:</u> 
<u>Equation 2:</u>
<u>Net chemical equation:</u> 
Hence, the net chemical equation is written above.
Answer:
Error percentage = 1.326% , 1.35% , 5.37%
density = mass / volume
For first sample:
density = 37.22/11.5 = 3.2365 g/ml
then percentage error = 100% - (3.2365/3.28 ) * 100 = 1.326%
For second sample:
density = 37.21/11.5 = 3.2356 g/ml
then percentage error = 100% - ( 3.2356 / 3.28 ) *100 = 1.35%
For third sample:
density = 37.25/12 = 3.104 g/ml
then percentage error = 100% - ( 3.104 / 3.28 ) *100 = 5.37%
Answer;
12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms.
Explanation:
Using a balanced chemical equation we can identify the number of carbon, hydrogen, and oxygen atoms in sugar.
CxHyOn + 12O₂ → 11 H₂O + 12CO₂
When an equation is completely balanced, then the number of each atom of an element is equal on the reactant side and the product side.
Therefore;
For carbon; x = 12
For Hydrogen; y = (11×2) = 22
For Oxygen; n + (12×2) = 11 + (12×2)
= n + 24 = 11 + 24
n = 11
Therefore the sugar has, 12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms.
Thus the balanced equation would be;
C₁₂H₂₂O₁₁ + 12O₂ → 11 H₂O + 12CO₂
Answer:
The given metal is beryllium.
Explanation:
Given data:
Mass of metal = 74 g
Volume of metal = 40 cm³
Which metal is this = ?
Solution:
First of all we will calculate the density.
it is mass divided by volume.
d = m/v
d = 74 g/40 cm³
d = 1.85 g/cm³
In literature it is given that the density of beryllium is 1.85 g/cm³. Thus given metal is beryllium.