Question

Calculate the molarity of each solution. 28.33 g c6h12o6 in 1.28 l of solution

Answer 1

Explanation:

Molarity is the number of moles present in a liter of solution.

Mathematically,     Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

And, no. of moles = $\frac{mass}{\text{molar mass}}$

Molar mass of $C_{6}H_{12}O_{6}$ is 180.15 g/mol. Therefore, number of moles present will be as follows.

                No. of moles = $\frac{mass}{\text{molar mass}}$                                                                                             = $\frac{28.33 g}{180.15 g/mol}$

                                      = 0.157 mol

Hence, calculate the molarity as follows.

                Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

                       = $\frac{0.157 mol}{1.28 L}$    

                       = 0.122 M

Thus, we can conclude that molarity of the solution is 0.122 M.

Answer 2

Molarity is number of moles of solute in 1 L of solution
number of moles of glucose  -28.33 g / 180 g/mol  = 0.1574 mol 
volume of solution is 1.28  L
since molarity is number of moles in 1 L
the number of moles in 1.28 L - 0.1574 mol
therefore number of moles in 1 L - 0.1574 mol / 1.28 L = 0.123 M
molarity is 0.123 M