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lozanna [386]
2 years ago
13

Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 6.3 parts

/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 870 samples is 6.4 ppm. Assume the variance is known to be 1.00. Does the data support the claim at the 0.1 level?
Step 4 of 5 : Enter the decision rule.
Mathematics
1 answer:
lbvjy [14]2 years ago
8 0
Ngnnghgfvnnfghbcxbnnfgjkb. Ccxc
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Use the rules for multiplication by powers of 10 to calculate 3 × 100. a. 3 b. 300 c. 30 d. 3,000
REY [17]
3*100
This can be rewritten as;
3*10^{2}
=300
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2 years ago
Which ordered pair is a solution of this equation?
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It’s A (-4,4) just plug the number and that your answer
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2 years ago
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alexi’s restaurant bill is $58, and he wants to leave a 20 percent tip. which expression represents the total amount that alexi
Alexeev081 [22]
He is leaving 20% tip of the bill of $58

20% extra

So total amount = 100% + 20% = 120%

120% of 58

(120/100) * 58

1.2 * 58

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So total amount Alexi needs to pay = $69.60
8 0
3 years ago
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A bacteria culture begins with 15 bacteria which double in amount at the end of every hour. How many bacteria are grown during t
elixir [45]
We use P = i•e^rt for exponential population growth, where P = end population, i = initial population, r = rate, and t = time
P = 2•i = 2•15 = 30, so 30 = 15 [e^(r•1)],
or 30/15 = 2 = e^(r)
ln 2 = ln (e^r)
.693 = r•(ln e), ln e = 1, so r = .693
Now that we have our doubling rate of .693, we can use that r and our t as the 12th hour is t=11, because there are 11 more hours at the end of that first hour
So our initial population is again 15, and P = i•e^rt
P = 15•e^(.693×11) = 15•e^(7.624)
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4 0
3 years ago
Read 2 more answers
A professor believes the students in a statistics class this term are more creative than most other students attending the unive
djverab [1.8K]

Answer:

Correct option: B

Step-by-step explanation:

The professor can perform a One-mean <em>t</em>-test to determine whether the average score of the students in his class is more than the average score of all the students attending university.

A <em>t</em>-test will be used instead of the <em>z</em>-test because the population standard deviation is not provided instead it is estimated by the sample standard deviation.

The hypothesis for this test can be defined as follows:

<em>H₀</em>: The average score of the students in his class is not more then the entire university, i.e. <em>μ ≤ 35</em>.

<em>Hₐ</em>: The average score of the students in his class is more then the entire university, i.e. <em>μ > 35</em>.

Given:

\bar x=40\\SE_{\bar x}=1.63

The test statistic is:

t=\frac{\bar x-\mu}{SE_{\bar x}}=\frac{40-35}{1.63}=3.0674\approx3.07

Thus, the correct option is (B).

4 0
2 years ago
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