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3 years ago

720 is what percent of $800?

Mathematics

1 answer:

dusya [7]3 years ago

4 0

the answer is 90 hope this help.

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Using that formula

d1i1m1o1n [39]

20% x 50 =(20 / 100) x 50 = (20 x 50) / 100 = 1000 / 100 = 10

answer is 10

8 0

4 years ago

Read 2 more answers

Please help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

mylen [45]

1 is for circle
2 is for triangle
3 is for surface area
4 is for volume

5 0

3 years ago

PLSSSS HELP >>>>>Solve the following inequality. Write your answer with no spaces in the inequalities and separat

Fofino [41]

Answer:

1x<5 or 0>0

Step-by-step explanation:

7 0

3 years ago

g If the economy improves, a certain stock stock will have a return of 23.4 percent. If the economy declines, the stock will hav

dusya [7]

Answer:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

Step-by-step explanation:

We can define the random variable of interest X as the return from a stock and we know the following conditions:

$X_1 = 23.4 , P(X_1) =0.67$ represent the result if the economy improves

$X_2 = -11.9 , P(X_1) =0.33$ represent the result if we have a recession

We want to find the standard deviation for the returns on the stock. We need to begin finding the mean with this formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing the data given we got:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

7 0

3 years ago

HELP ME PLZ I BEG YOU

Dmitry [639]

Answer:

Option H

Step-by-step explanation:

<u>Step 1: Determine which option is correct</u>

Option F: The mode/most common number in Store 1 is 2 which the mode of Store 2 is 1. So... the first option is not correct.

Option G: The range for both of the data sets are 6. So... the second option is not correct.

Option H: The mean/average of Store 1 is 2.9 which the mean/average for Store 2 is 2. So... this option is correct because store 1 does have a higher mean than store 2.

Answer: Option H

6 0

3 years ago