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Alika [10]
3 years ago
6

Help would be much appreciated

Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

D: 5

E: -2x

F: x^1

Step-by-step explanation:

4*5=20

-14x/7=-2x

x^3/x^2=x^1

the last one may not be write but I think that they are all correct

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Somebody please help !!
andreyandreev [35.5K]

Answer:

A'(6,8)

B'(6,2)

C'(2,2)

Step-by-step explanation:

You can find the vertices by finding the X and Y coordinates in the plane, after rotating it 180 degrees.

7 0
3 years ago
Solve (x - 5)^2=3 <br><br> thank you in advance
sashaice [31]
Im not sure how to put the sign here but x= long division sign 3+5, negative sign in front of long division sign 3+5
3 0
3 years ago
What is the value of the expression, below, when x = 2 and y = 4?
allochka39001 [22]

Solution:

\frac{4x + y}{2y - x}

Numerator - 4x + y = 8 + 4 = 12

Denominator - 2y - x = 8 - 2 = 6

Final Answer:

12/6 = 2


3 0
3 years ago
(100) What’s the distance of all the sides combined, add the method.
Nezavi [6.7K]

Answer:

10cm2

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
A ball is thrown into the air with an initial upward velocity of 48dt/s. Its height h in feet after t seconds is given by the eq
slavikrds [6]

Answer:

Step-by-step explanation:

The equation used to represent the height of the ball, h in feet after t seconds is expressed as

h = -16t^2 + 48t + 4

A) The height of the ball after 2 seconds would be

h = - 16 × 2² + 48 × 2 + 4

h = - 64 + 96 + 4

h = 36 feet

B)The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the rocket.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = -16

b = 48

Vertex = - - 48/32= 1.5

So the ball will attain maximum height at 1.5 seconds.

C) The maximum height of the ball would be

h = -16 × 1.5² + 48 × 1.5 + 4

h = - 36 + 72 + 4

h = 40 feet

3 0
4 years ago
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