Answer:
Number of fish in 2006 = 845 fishes (Approx.)
Step-by-step explanation:
Given;
Number of fish in 2000 = 1,150 fishes
Decreasing rate = 5% per year
Find:
Number of fish in 2006
Computation:
Exponential decay function:
F = P[1-r]ⁿ
Number of year = 2006 - 2000
Number of year = 6 year
Number of fish in 2006 = 1,150[1-5%]⁶
Number of fish in 2006 = 1,150[1-0.05]⁶
Number of fish in 2006 = 1,150[0.95]⁶
Number of fish in 2006 = 1,150[0.735]
Number of fish in 2006 = 845.25
Number of fish in 2006 = 845 fishes (Approx.)
Answer:
(x) = │ x - 4│+ 3
Step-by-step explanation:
Step-by-step explanation:
Hey there!
The midpoint formula is;

Where, (x1), (y1), (x2) and (y2) are the given coordinates.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Lets get started :)
We need to find the radius of the larger cylinder
V =

r²h
960 =

r²(16)

60 =


r =

r ≈ 4.27 cm
The ratio of the bigger cylinder to smaller is:
16 : 4
Therefore, the big cylinder is 4 times bigger than the small cylinder

= r
r = 1.09 cm (radius of small cyclinder)
V (small cylinder) =

(1.09)²(4)
= 15 cm³Your answer will be C. 15 cm³
<span>Exponent
is a number used to express shorter equation; it is a number that says how many
times you are going to multiply the base number.
</span><span>
Exponents have several laws, here are
some:
=> x^1 = x
=> x^0 = 1
=> x^-1 = 1/x
=> x^m x^n = X^m+n
=> x^m/x^n = x^m-n
And since we were asked to write an
expression with a negative exponent that has a value between 0 and ½
=> 2^ -2 = ½
</span>