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Orlov [11]
3 years ago
8

What is the diameter of a circular swimming pool with a radius of 9 feet? Enter only the number

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
8 0

Answer:d=18FT

Step-by-step explanation:

YOUR WELCOM :)

11111nata11111 [884]3 years ago
5 0
The diameter is double the radius of the circle. So you would do 9*2 = 18 feet.

The question only asks for the number though so you can just enter 18.
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Use the Laplace transform to solve the given initial value problem. y' + 6y = e^4t ; y(0)=2 ...?
TiliK225 [7]
Performing laplace transform of the equation.

sY(s) - y(0) + 6Y(s) = 1/(s-4)
(s+6)Y(s) - 2 = 1/(s-4)
Y(s) = 2/(s+6) + 1/(s-4)(s+6), by partial fraction decomposition
Y(s) = 2/(s+6) + 1/10 * (1/(s-4) + 1/(s+6))
Y(s) = 0.1/(s-4) + 2.1/(s+6)

Performing inverse laplace transform,
y(t) = 0.1e^4t + 2.1e^(-6t)


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
Solve for 3(2x-1)+7=6x-3-2(-4x)
Svetllana [295]

Answer:

x = 1.14

Step-by-step explanation:

3(2x - 1) + 7 = 6x - 3 - 2(-4x) [Given Equation]

6x - 3 + 7 = 6x - 3 + 8x [Distributive Property]

6x + 4 = 14x - 3 [Combine like-terms]

-8x + 4 = -3 [Subtraction Property of Equality]

-8x = -7 [Subtraction PoE]

x = 1.14 [Division PoE]

3 0
3 years ago
How do you rationalise this surd?
Ksivusya [100]

\frac{1 +  \sqrt{3} }{ \sqrt{2} }   \times  \frac{ \sqrt{2} }{ \sqrt{2} } =  \frac{ \sqrt{2}  +  \sqrt{6}  }{2}
here you go
5 0
3 years ago
Read 2 more answers
X4 – x3 – 9x2 – 3x + 1 = 0
Diano4ka-milaya [45]

Answer: are we just simplifying?

Step-by-step explanation:

6 0
3 years ago
2. Carissa also has a sink that is shaped like a half-sphere. The sink has a volume of 3617 in3. One day, her sink clogged. She
sleet_krkn [62]

Answer:Yes, your answers are correct.

The volume of a cone is given by V = 1/3πr²h.  Since the diameter of the first cone is 4, the radius is 2; therefore the volume is

V = 1/3π(2²)(8) = 32π/3

We divide the volume of the sink, 2000π/3, by the volume of the cone:

2000π/3 ÷ 32π/3 = 2000π/3 × 3/32π = 6000π/96π = 62.5 ≈ 63.

The diameter of the second conical cup is 8, so the radius is 4.  The volume then is:

V = 1/3π(4²)(8) = 128π/3

Dividing the volume of the sink, 2000π/3, by 128π/3:

2000π/3 ÷ 128π/3 = 2000π/3 × 3/128π = 6000π/384π = 15.625 ≈ 16

Step-by-step explanation:

8 0
2 years ago
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