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3 years ago

why are being flammable and combustible be considered to be chemical properties and not physical properties?

Chemistry

1 answer:

Alinara [238K]3 years ago

5 0

Answer:

Because combustion is a chemical change and not a physical change. Do, flammable and combustible gases burn and change into new substance.

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What does it mean for a chemical to have a low potential energy?

katrin [286]

Low potential energy means there are fewer chemical bonds so H2O has Less than C6H12O6 because their are less valence electrons making bonds with others. in an endothermic reaction heat goes into the product so the reactants would have less potential energy.

4 0

3 years ago

A passenger elevator travels from the first floor to the 60th floor, a distance of 210 m, in 35s. What is the elevator’s speed?

d1i1m1o1n [39]

Answer:6m per second

Explanation:

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3 years ago

A 50.0 mL sample of waste process water from a food processing plant weighing 50.1 g was placed in a properly prepared crucible

RideAnS [48]

Answer:

TS (total solid, mg/L) = 57,174 mg/L

VS (volatile solid, mg/L) = 24,088 mg/L

Explanation:

First step to solve this problem is to know data and questions:

Data:

Sample volume = 50 mL

Sample weight = 50.1 g

P1 (weight empty crucible) = 17.1234 g

P2 (weight after drying a 103º in oven) = 19.9821 g

P3 (weight after incinatrion 550º) = 18.7777 g

Questions:

TS = ?

VS = ?

Formula:

We need to use formulas to calculate total solid (TS) and volatile solid (VS), these are:

$TS =\frac{(P2-P1)*\frac{1,000 mg}{1g} }{Sample volumen (L)}$

$VS = \frac{(P2-P3)*\frac{1,000 mg}{1g} }{Sample volume (L)}$

We have to transform mL to L so we will divide mL by 1,000 the sample volume:

$Sample Volumen (L) = 50 mL * \frac{1L}{1,000 mL} = 0.05 L$

In the formula the value of 1,000 results by the convertion factor to transform grams to miligrams (we have to multiplie by 1,000)

Now we need to replace data on previous formulas and we will get TS and VS expressed in mg/L:

$TS = \frac{(19.9821 g-17.1234g)*\frac{1,000 mg}{1g} }{0.05L} = 57,174mg/L$

$VS = \frac{(19.9821g-18.7777g)*\frac{1,000mg}{1g} }{0.05L}=24,088 mg/L$

We divide TS and VS formula by sample volume because the exercise is asking us to express the results in mg/L.

4 0

3 years ago

(science) hurry help!! All commonly abused drugs are illegal. true or false

Lubov Fominskaja [6]

Answer:

False

Explanation:

Many abused drugs are prescription drugs.

8 0

3 years ago

Read 2 more answers

The concentration of glucose, C6H12O6, in normal spinal fluid is 75 mg/100g. What is the molality of the solution

galben [10]

Answer:

4.16x10⁻³m

Explanation:

Molality is defined as the ratio between moles of a solute, in this case glucose, and kg of solvent.

As there are 100g of solvent, the kg are 0.1. Thus, we only need to calculate from the mass of glucose its moles to solve the molality of the solution.

Moles glucose:

There are 75mg = 0.075g of glucose. To conver mass to moles it is necessary molar mass.

Molar mass glucose:

6C = 12.01g/mol*6 = 72.06g/mol

12H = 12*1.008g/mol = 12.10g/mol

6O = 6*16g/mol = 96g/mol

72.06 + 12.10 + 96 = 180.16g/mol

Moles of 0.075g of glucose:

0.075g * (1 mol / 180.16g) =

4.16x10⁻⁴ moles of glucose

Molality of the solution:

4.16x10⁻⁴ moles of glucose / 0.1kg of solvent =

7 0

4 years ago