Ask question

Ask question

All categories

2 years ago

9

I’m doing real numbers and i can’t figure out which box to cheCk

1 answer:

Tju [1.3M]2 years ago

8 0

Is there a picture of the work? btw ALL numbers are real numbers.

You might be interested in

Select all of the given trigonometric equations that are true statements. sin(180°) = cos(0°) cos(74°) = sin(16°) sin(20°) = cos

lara [203]

Answer:

Cos 74°= Sin 16°

Sin 20°= Cos 70°

Sin A°=Cos (90°- A°)

Step-by-step explanation:

This is because the three pairs are complementary i.e they add up to 90° and in trigonometric ratios, complementary ratios are equal.

3 0

2 years ago

Find the slope of the line that passes through the points (-4, 3) and (6, -2).

Norma-Jean [14]

Answer:

-1/2

Step-by-step explanation:

using the slope formula 3-(-2)/-4-6=-1/2

5 0

2 years ago

Read 2 more answers

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

2 years ago

(PLS HELP NOW WILL GIVE BRINIEST!!!!!) A figure is formed by two pairs of parallel sides that are the same length. Which type of

Gekata [30.6K]

Answer: B. Square

Step-by-step explanation:

All sides of a square have the same length
All four angles of a square = 90°
A square has two parallel sides

4 0

2 years ago

Read 2 more answers

Section 5.2 Problem 6:<br><br>Find the general solution<br><img src="https://tex.z-dn.net/?f=y%27%27%20%2B%206y%27%20%2B%2010y%2

mihalych1998 [28]

Answer:

$y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Step-by-step explanation:

<u>Given Second-Order Homogenous Differential Equation</u>

$y''+6y'+10y=0$

<u>Use Auxiliary Equation</u>

<u /> $m^2+6m+10=0\\\\(m+3)^2+1=0\\\\(m+3)^2=-1\\\\m+3=\pm i\\\\m=-3\pm i$

<u>General Solution</u>

<u /> $y=e^{pt}(A\: cos\: qt+B\:sin\:qt)\\\\y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Note that the DE has two distinct complex solutions $p\pm qi$ where $A$ and $B$ are arbitrary constants.

4 0

1 year ago