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klasskru [66]
2 years ago
11

If complex number z = 3 Left-bracket cosine (StartFraction 3 pi Over 2 EndFraction) + I sine (StartFraction 3 pi Over 2 EndFract

ion) right-bracket, then complete the statements for z4.
The modulus of z4 would be


The coefficient in front of the argument (or angle) of z4 would be


ANSWER: 81

ANSWER: 4
Mathematics
2 answers:
amid [387]2 years ago
4 0

Answer:

b

Step-by-step explanation:

larisa [96]2 years ago
3 0

Answer:

81 4

Step-by-step explanation:

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While visiting a​ memorial, a person approximated the angle of elevation to the top of the memorial to be 35º. After walking 255
Alenkasestr [34]

Draw a diagram to illustrate the problem as shown in the figure below.

Let h the height of the hill. =

At position A, the angle of elevation is 40°, and the horizontal distance to the foot of the hill is x.

By definition,

tan(40°) = h/x h = x tan40 = 0.8391x

(1)

At position B, Joe is (x - 450) ft from the foot of the hill. His angle of elevation is

40 + 18 = 58°.

By definition, tan(58°) = h/(x - 450)

h = (x - 450) tan(58°) = 1.6003(x-450)

h = 1.6003x - 720.135 (2)

Equate (1) and (2).

1.6003x - 720.135 = 0.8391x 0.7612x = 720.135

x = 946.0523

From (1), obtain

h = 0.8391*946.0523 = 793.8 ft

Answer: The height of the hill is approximately 794 ft (nearest integer)

6 0
2 years ago
Can you help me with this question? I am having difficulty identifying Terms
melomori [17]
Theres no question here

3 0
3 years ago
Simplify: ( 1^0+2^1+3^2) ÷ 22/ 5^0​
Aleksandr-060686 [28]

Step-by-step explanation:

( 1 + 2 + 9 ) ÷ 22/ 1

12 ÷ 22

6 ÷ 11

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7 0
3 years ago
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Whats is simplify 10 over 25
malfutka [58]
10/25 = 2/5 Because you divide both sides by 5

5 0
3 years ago
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How do you find the area of the shaded sector of the circle? The radius is 10in and the sector is 45 degrees
Step2247 [10]

Given:

Radius of the circle = 10 in

Central angle of the sector = 45 degrees

To find:

The area of the sector.

Solution:

Area of a sector is

A=\dfrac{\theta}{360^\circ}\pi r^2

Where, \theta is the central angle in degrees.

Putting r=10 and \theta=45^\circ, we get

A=\dfrac{45^\circ}{360^\circ}\pi (10)^2

A=\dfrac{1}{8}\pi (100)

A=12.5\pi

Therefore, the area of the sector is 12.5π sq. inches.

7 0
3 years ago
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