A bag contains 10 blue counting chips and 10 red counting chips. What is the probability that, without looking, Miguel will pick
a blue chip first, which he will keep, and on his second draw Miguel will select a red chip?
1/10
11/21
5/38
5/19
1 answer:
Answer: 5/19
Step-by-step explanation:
(probability of blue chip)/(total chips) x (probability of red chip)/(new total chips)
10/20 x 10/19 = 100/380
simplify: 5/19
You might be interested in
Hello,
f^(-1)(f(x))=f^(-1)(1/2 * x)=2*(1/2 * x)=(2*1/2)*x=1*x=x
f(f^(-1)(x))=f(2x)=1/2* (2x)=(1/2*2)*x=1*x=x
The answer would be C. Hope this works
Answer:
(2,6)
Step-by-step explanation:
y = 2x + 2
Y = 3x
2x+2=3x
2x-3x+2=0
-x+2=0
-x=-2
x=2
y=3(2)=6
Answer:
25.821568896
Step-by-step explanation:
Answer:
28
Step-by-step explanation:
2(7)(2) =28