Answer:
160
Step-by-step explanation:?
The regression equation for the data given is y= -8.57 -2.31x
Step-by-step explanation:
The first step is to form a table as shown below;
x y xy x² y²
1 4 4 1 16
2 1 2 4 1
3 5 15 9 25
4 10 40 16 100
5 16 80 25 256
6 19 114 36 361
7 15 105 49 225
28 60 360 140 984 ------sum
A linear regression equation is in the form of y=A+Bx
where ;
x=independent variable
y=dependent variable
n=sample size/number of data points
A and B are constants that describe the y-intercept and the slope of the line
Calculating the constants;
A=(∑y)(∑x²) - (∑x)(∑xy) / n(∑x²) - (∑x)²
A=(60)(140) - (28)(360) / 7(140)-(28)²
A=8400 - 10080 /980-784
A= -1680/196
A= - 8.57
B= n(∑xy) - (∑x) (∑y) / n(∑x²) - (∑x)²
B= 7(360)-(28)(60) / 7(60) - (28)²
B=2520 - 1680 /420-784
B=840/-364
B= -2.31
y=A+Bx
y= -8.57 -2.31x
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Answer:
y=2x-11
Step-by-step explanation:
Put it in the form y=mx+b=>y=2x-1/2. Instead of -1/2, put it as b, since you want it to go through 3,-5. y=2m+b when it goes through (3,-5) happens when -5=3*2-b. Do algebra, and get b as 11. That means the equation is y=2x-11.
A vertical line that the graph of a function approaches but never intersects. The correct option is B.
<h3>When do we get vertical asymptote for a function?</h3>
Suppose that we have the function f(x) such that it is continuous for all input values < a or > a and have got the values of f(x) going to infinity or -ve infinity (from either side of x = a) as x goes near a, and is not defined at x = a, then at that point, there can be constructed a vertical line x = a and it will be called as vertical asymptote for f(x) at x = a
A vertical asymptote can be described as a vertical line that the graph of a function approaches but never intersects.
Hence, the correct option is B.
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Answer:
Step-by-step explanation:
is the expression given to be solved.
First of all let us have a look at <u>3 formulas</u>:
Both the formula can be applied to the expression() during the first step while solving it.
<u>Applying formula (1):</u>
Comparing the terms of 
with 
So, is reduced to
<u>Applying formula (2):</u>
Comparing the terms of with 
So, is reduced to .
So, the answers can be:
