Answer:

Step-by-step explanation:
To find a line that is perpendicular to 8x + 3y = -6 and goes through (-24, 2), lets first find what the line's slope would be.
We can find this by finding the slope of 8x + 3y = -6 and taking the negative reciprocal of it.
We can find the slope of that line by putting it in slope-intercept form:
8x + 3y = -6
Subtract 8x from both sides.
3y = -6 - 8x
Divide both sides by 3.


So the slope of that line would be -8/3.
The negative reciprocal of -8/3 would be 3/8.
Now we know that the new line would have to pass through the point (-24, 2). We can use this point and write the equation in point-slope form:

Now lets change this into slope-intercept form. Add 2 to both sides.

Distribute the 3/8.

Simplify.

And now we have our equation in slope-intercept form.
I hope you find this helpful.
Answer:
m=4
Step-by-step explanation:
We are to find the value of m in the question
1.75+0.75m=4.75
Let's start by substrating 1.75 from both sides
0.75m=3
We will have to make m the subject of formula by dividing both sides by 0.75
m=4
Therefore the final answer for m is 4
Answer:
The first plane is moving at 295 mph and the second plane is moving at 355mph.
Step-by-step explanation:
In order to find the speed of each plane we first need to know the relative speed between them, since they are flying in oposite directions their relative speed is the sum of their individual speeds. In this case the speed of the first plane will be "x" and the second plane will be "y". So we have:
x = y - 60
relative speed = x + y = (y - 60) + y = 2*y - 60
We can now apply the formula for average speed in order to solve for "y", we have:
average speed = distance/time
average speed = 1625/2.5 = 650 mph
In this case the average speed is equal to their relative speed, so we have:
2*y - 60 = 650
2*y = 650 + 60
2*y = 710
y = 710/2 = 355 mph
We can now solve for "x", we have:
x = 355 - 60 = 295 mph
The first plane is moving at 295 mph and the second plane is moving at 355mph.
Answer:
The answer is 84.08
Step-by-step explanation:
1) line up the decimal points
2) add it up like any addition problem
3) Place the decimal point right under the placement of the decimal point of the problem