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Svetlanka [38]
3 years ago
12

What's the price of something that's $69.80 but has a 60% discount ​

Mathematics
2 answers:
zhuklara [117]3 years ago
7 0

Answer:

price = $116.3

Step-by-step explanation:

x*60%= 69.80

x= 69.80/0.6

x= $116.33 (original price)

sveticcg [70]3 years ago
5 0

Answer:

$116.33.

Step-by-step explanation:

By proportion it is:

69.80 / 0.60

= $116.33.

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A 21-inch piece of steel is cut into three pieces so that the second piece is twice as long as the first piece, and the third pi
Pavel [41]
****hope this helps****

7 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
Which equation is not equal to 6^3/6^6 ?: 1/6^2 6^-3 1/216 1/6^3
SCORPION-xisa [38]
The answer would be 60 because its multiplication all those numbers

4 0
3 years ago
PLEASE HELP IM STUCK ON A PROBLEM....
sleet_krkn [62]

Answer:

Number line A.

Step-by-step explanation:

|-5x| - 11 = -1

Add 11 to both sides.

|-5x| = 10

-5x = 10 or -5x = -10

x = -2 or x = 2

Answer: Number line A.

5 0
3 years ago
A cyclist rides his bike at a speed of 18 miles per hour. What is this speed in kilometers per hour? How many kilometers will th
Sonja [21]

Well, if 1 mile = 1.6 kilometers and he's traveling at 18mph, then do 18 x 1.6 which = 28.8.

So, this is his current speed in kph

3 x 28.8 = 86.4‬

They will have traveled 86.4‬ kilometers

(I haven't worked with this kind of math in a while so correct me if I'm wrong!)

4 0
3 years ago
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