Given set S = <span>{A, B, C, D, E, F, G, H}
There are 8 elements in set S and we are to choose 3 letters at random, the number of ways to choose such is x. It is simply similar to choosing 5 letters at random, which is also equal to x. Since order doesn't matter, n! / (n-m)! where n = 8 and m = 3, which is 336 ways. </span>
X - 1/2 (if you meant the difference between)
B=8. A^2+B^2=C^2. This means 6to the second power plus B to the second power equals10 to the second power. 36+b^2=100. B to the second power equals 64. Square root of 64 is 8, so B equals 8
Answer:
I think you would divide all of your numbers.
Step-by-step explanation:
Answer:
i think X is 9 and y is 5
Step-by-step explanation:
