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zhuklara [117]
2 years ago
15

X is an even 3-digit integer ending to zero. Which of the following is an

Mathematics
2 answers:
insens350 [35]2 years ago
5 0

Answer: Don't know sorry

Step-by-step explanation:

eduard2 years ago
4 0

Answer:

thanks for the points

Math

WE ARE HERE TO ADD WHAT WE CAN TO LIFE NOT TO GET WHAT WE CAN FROM IT

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Find the 12th term of the geometric sequence 5, -25, 125, ...5,−25,125,...
katovenus [111]

Answer:

  • a_{12}=-244140625

Step-by-step explanation:

Considering the geometric sequence

5,-25,\:125,\:...

a_1=5

As the common ratio 'r' between consecutive terms is constant.

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

r=\frac{-25}{5}=-5

r=\frac{125}{-25}=-5

The general term of a geometric sequence is given by the formula:  

a_n=a_1\cdot \:r^{n-1}

where a_1 is the initial term and r the common ratio.

Putting n = 12 , r = -5 and a_1=5 in the general term of a geometric sequence to determine the 12th term of the sequence.

a_n=a_1\cdot \:r^{n-1}

a_n=5\left(-5\right)^{n-1}

a_{12}=5\left(-5\right)^{12-1}

      =5\left(-5^{11}\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

       =-5\cdot \:5^{11}

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

        =-5^{1+11}     ∵ 5\cdot \:5^{11}=\:5^{1+11}

        =-244140625

Therefore,

  • a_{12}=-244140625
6 0
3 years ago
HELP 1x3 divided by 56 then multiply that by 9
Sloan [31]

Answer:

0.48

Step-by-step explanation:

1x3/56 then multiply it by 9

1x3 is 3  

3 x 9 = 27

27/56  this fraction cant be reduced so if you count it or put it in a calculator you'll get 0.482143

8 0
3 years ago
It was reported that 23% of U.S. adult cellphone owners called a friend for advice about a purchase while in a store. If a sampl
leva [86]

Answer:

P(X=7)

And using the probability mass function we got:

P(X=7)=(15C7)(0.23)^7 (1-0.23)^{15-7}=0.0271  

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.23)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want to find the following probability:

P(X=7)

And using the probability mass function we got:

P(X=7)=(15C7)(0.23)^7 (1-0.23)^{15-7}=0.0271  

5 0
3 years ago
HELP WITH THIS MATH!!! IM TIMED
Wittaler [7]

Answer:

Table C)

Step-by-step explanation:

y=-x+3\\x+y=3\\Hence,\\Considering\ Table\ C\,\\Substituting\ x=-3,y=6\\6=3+3\\6=6 (LHS=RHS)\\\\Substituting\ x=0, y=3\\3=3 (LHS=RHS)\\\\Substituting\ x=3, y=0,\\0=-(3)+3\\0=0 (LHS=RHS)

4 0
2 years ago
Read 2 more answers
AX + B = C what is X equal to?
elena-14-01-66 [18.8K]

Answer:

x is a variable

Step-by-step explanation:

what happens an squared plus B equals C and what I want to do is solve for a so again what we want to do is when we're taking solver a we want to isolate the variable get the variable by itself so the data that need to look at well what is happening on my variable a well you can see me as being multiplied by X and it's being added by B so I need to undo those but we got to make sure we undo them in a certain upper certain order which we call the reverse order of operations which is like the order of operations but the reverse method meaning I'm gonna undo addition or subtraction first so you can see that since my variable a is being added by B I need to undo that by subtracting B and I'll use my subtraction property of equality that's going to now subtract a 0 and then these C minus B are not like terms so I'm going to write ax is equal to C minus B now I need to solve for a so I need to look at and say alright my a is being x over X so the inverse operation of multiplying is dividing by X so therefore have a equals C minus B divided by X now sometimes you could say alright that's correct but we could also divide this X into both of these terms and I'm going to rewrite this in a different form I could say a equals C over X minus B over X alright so what I'm doing is are just dividing those through

hope this helps

5 0
3 years ago
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