Answer:




Step-by-step explanation:
The probability mass function P(X = x) is the probability that X happens x times.
When n trials happen, for each
, the probability mass function is given by:

In which p is the probability that the event happens.
is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

The sum of all P(X=x) must be 1.
In this problem
We have 3 trials, so 
The probability that a wafer pass a test is 0.7, so 
Determine the probability mass function of the number of wafers from a lot that pass the test.




Answer:(5/3,5/3)
Step-by-step explanation: I did the test ;D
N=1→an=a1 (first term)=16 (on the graph for n=1)→First term = 16
n=2→an=a2 (second term) = 4 (on the graph for n=2)→Second term = 4
ratio=(Second term)/(First term)=a2/a1=4/16
Simplifying the fraction dividing the numerator (4) by 4 and the denominator (16) by 4:
ratio=(4/4)/(16/4)→ratio=1/4
Answer: Option A. First term = 16, ratio = 1/4
Answer:

Step-by-step explanation:
Given
![A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%266%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D)
Required
Determine the determinant
For a two by two matrix, A such that:
![A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
The determinant |A| is:

So, in
![A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%266%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D)
The determinant is:


