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Ilya [14]
3 years ago
15

10/50 the ratio as a fraction in simplest form

Mathematics
2 answers:
Tpy6a [65]3 years ago
6 0

To find the simplest form of the ration divide the numerator and denominator by the GCF of both numbers. In this case the GCF is 10. (GCF means the Greatest Common Factor).

10÷10/50÷10 = 1/5

Best of Luck!

Pani-rosa [81]3 years ago
6 0

Answer:

To find the simplest form of the ration divide the numerator and denominator by the GCF of both numbers. In this case the GCF is 10. (GCF means the Greatest Common Factor).

10÷10/50÷10 = 1/5

Best of Luck!

Read more on Brainly.com - brainly.com/question/14604885#readmore

Step-by-step explanation:

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In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t
Angelina_Jolie [31]

Answer:

P(X = 0) = 0.027

P(X = 1) = 0.189

P(X = 2) = 0.441

P(X = 3)= 0.343

Step-by-step explanation:

The probability mass function P(X = x) is the probability that X happens x times.

When n trials happen, for each x \leq n, the probability mass function is given by:

P(X = x) = pe_{n,x}.p^{x}.(1-p)^{n-x}

In which p is the probability that the event happens.

pe_{n,x}, is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

pe_{n,x} = \frac{n!}{x!}

The sum of all P(X=x) must be 1.

In this problem

We have 3 trials, so n = 3

The probability that a wafer pass a test is 0.7, so p = 0.7

Determine the probability mass function of the number of wafers from a lot that pass the test.

P(X = 0) = (0.7)^{0}.(0.3)^{3} = 0.027

P(X = 1) = pe_{3,1}.(0.7).(0.3)^{2} = 0.189

P(X = 2) = pe_{3,2}.(0.7)^{2}.(0.3) = 0.441

P(X = 3) = (0.7)^{3} = 0.343

5 0
3 years ago
On a coordinate plane, an image rectangle has points (negative 5, 0), (5, 0), A prime (5, negative 5), (negative 5, negative 5).
aev [14]

Answer:(5/3,5/3)

Step-by-step explanation: I did the test ;D

6 0
2 years ago
Read 2 more answers
A class had 11 boys and 9 girls in it. What percent of the class are boys?
scZoUnD [109]

11 divided by 20 = .55

multiply that by 100

55% is your answer

6 0
3 years ago
Read 2 more answers
Please please help me with this
swat32
N=1→an=a1 (first term)=16 (on the graph for n=1)→First term = 16
n=2→an=a2 (second term) = 4 (on the graph for n=2)→Second term = 4

ratio=(Second term)/(First term)=a2/a1=4/16
Simplifying the fraction dividing the numerator (4) by 4 and the denominator (16) by 4:
ratio=(4/4)/(16/4)→ratio=1/4

Answer: Option A. First term = 16, ratio = 1/4
7 0
3 years ago
Find the determinant of the following matrix. A =<br>-2 6<br>3 5​
Blababa [14]

Answer:

|A| = - 28

Step-by-step explanation:

Given

A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]

Required

Determine the determinant

For a two by two matrix, A such that:

A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]

The determinant |A| is:

|A| = a * d - b * c

So, in

A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]

The determinant is:

|A| = -2 * 5 - 6 * 3

|A| = -10 - 18

|A| = - 28

6 0
3 years ago
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