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Eduardwww [97]
3 years ago
15

Yo ill give brainliest if ur right help pls​

Mathematics
2 answers:
Savatey [412]3 years ago
6 0

Answer:

B or C. Im thinking C.

Step-by-step explanation:

tester [92]3 years ago
3 0

Answer:

C, look at the problem and it says plus" directly look at the option and compare.

Step-by-step explanation:

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How do Solve These?????????
svlad2 [7]

Answer:

The slope of the parallel lines would be the same but the slope of the perpendicular lines would be the reciprocal

Step-by-step explanation:

To find a reciprocal for 1, 3, 4, 5, and 9 (whole numbers) just put a 1 over the number to make it a fraction and for 2, 6, 7, 8, and 10 (fractions) just flip it.

For example 1 would be 1/10 and 2 would be 3/2

8 0
4 years ago
Read 2 more answers
Which of the following expressions represents the product below?
Tresset [83]

Answer:

(4 i+ 3)(5 - 2i)

= -   {8i}^{2} +  20i + 15 - 6i

= -   {8i}^{2} +  14i + 15

6 0
4 years ago
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
sladkih [1.3K]

Answer:

(a) The probability that a randomly selected adult is either overweight or obese is 0.569.

(b) The probability that a randomly selected adult is neither overweight nor obese is 0.431.

Step-by-step explanation:

Let <em>A</em> = a person is over weight and <em>B</em> = a person is obese.

The information provided is:

An adult is considered overweight if the BMI ≥ 25 but BMI < 30.

An obese adult will have a BMI ≥ 30.

According to the range of BMI the events A and B are independent.

P (A) = 0.331 and P (B) = 0.357.

(a)

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P (A ∪ B) = P (A) + P (B) - P (A ∩ B)

               = P (A) + P (B) - P (A)×P (B)

               =0.331+0.357-(0.331\times0.357)\\=0.569833\\=0.569

Thus, the probability that a randomly selected adult is either overweight or obese is 0.569.

(b)

Compute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(A^{c}\cup B^{c})=1-P(A\cup B)=1-0.569=0.431

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.431.

4 0
4 years ago
What is the scientific notation for 0.000085
VikaD [51]
0.85 X 10 to the 3 power

5 0
3 years ago
Please help ASAP!
Nina [5.8K]

It is given in the question that

2(2x-1)>6 \ or \ x+3 \leq -6

For th first inequality, we divide both sides by 2, and for second, we subtract 3 to both sides, that is

2x-1>3 \ or \ x \leq -6-3&#10;\\&#10;2x>4 \ or \ x \leq -9&#10;\\&#10;x>2 \ or \ x \leq -9

So the required inequality is

(- \infty, -9] U (2, \infty)

Correct option is B

7 0
3 years ago
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