In order for a function to be odd, we know that f(-x) = -f(x)
Hence, the only graphs that are odd are the cubics.
Now, a monomial is defined as an equation with only one term in it. Since the first two is shifted, they must consist of at least 2 terms.
Hence, the only viable answer is the third graph.
I'm gonna gonna go with C
.hello :
<span>2d−e=7....(1)
d+e=5.....(2)
(1)+(2) : 3d=12
d=4
subsct in (2) :
4+e=5
e=1
conclusion :
</span><span>The solution is (4, 1).</span><span>
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