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2 years ago

For k:(j + k)/3 = 5

Mathematics

2 answers:

enyata [817]2 years ago

5 0

Answer:

ok ill help you can u or someone help me :(

and now my turn

Do you think that the situation should be different and, if so, how?:

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4+ senteses

Sphinxa [80]2 years ago

4 0

Answer:

k=-j=15

Step-by-step explanation:

See attachment for step by step :)

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What is the difference of 13.2 - 6.56

vichka [17]

Answer:

6.64

Step-by-step explanation:

Subtract : 13.2 - 6.56

13.2(0)

-6.56

----------

6.64

8 0

2 years ago

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Are the equations 9x=5x+4 and 14x=4 equivilant?

Paha777 [63]

Answer:

Step-by-step explanation:

First solve both equations:

1) 9x = 5x + 4

Simplifying

9x = 5x + 4

Reorder the terms:

9x = 4 + 5x

Solving

9x = 4 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.

9x + -5x = 4 + 5x + -5x

Combine like terms: 9x + -5x = 4x

4x = 4 + 5x + -5x

Combine like terms: 5x + -5x = 0

4x = 4 + 0

4x = 4

Divide each side by '4'.

x = 1

Simplifying

x = 1

2) 14x = 4

14x = 4 (divide both sides by 14 to get x)

14x/14 = 4/14

x = 0.285714285714

As you can see, the value of x in the second equations is less than one, therefore making these algebraic equations not equivalent.

4 0

2 years ago

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Solve the equatuon x/2-(2/(x+1))=1 x=?

Snezhnost [94]

$\frac{x}{2}-\frac{2}{x+1}=1$

We have 2 denominators that we need to get rid of. Whenever there are the denominators, all we have to do is multiply all whole equation with the denominators.

Our denominators are both 2 and x+1. Therefore, we multiply the whole equation by 2(x+1)

$\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]$

Then shorten the fractions.

$\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]\\x(x+1)-2(2)=1(2x+2)$

Distribute in all.

$x^2+x-4=2x+2$

We should get like this. Because the polynomial is 2-degree, I'd suggest you to move all terms to one place. Therefore, moving 2x+2 to another side and subtract.

$x^2+x-4-2x-2=0\\x^2-x-6=0\\$

We are almost there. All we have to do is, solving for x by factoring. (Although there are more than just factoring but factoring this polynomial is faster.)

$(x-3)(x+2)=0\\x=3,-2$