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katrin2010 [14]
2 years ago
10

7x-3y=-12. Name 2 possible answers for (x,y)

Mathematics
1 answer:
anzhelika [568]2 years ago
6 0

Answer:

x = (-12/7 , 0)

y= (0,4)

Step-by-step explanation:

Plug y=0 into the equation and solve the resulting equation 7x=−12 for x

7x = -12

/7      /7

x = -12/7     and y =0

Plug x=0 into the equation and solve the resulting equation −3y=−12 for y

-3y = -12

/-3     -3

Y = 4        and X = 0

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3 years ago
The amounts of electricity bills for all households in a city have a skewed probability distribution with a mean of $139 and a
ZanzabumX [31]

Answer:

P (within $6 of 4) = 0.9164

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

Mean of $139 and a standard deviation of $30.

This means that \mu = 139, \sigma = 30

Random sample of 75 households

This means that n = 75, s = \frac{30}{\sqrt{75}} = 3.464

75 > 30, which means that the sampling distribution is approximately normal.

Find the probability that the mean amount of electric bills for a random sample of 75 households selected from this city will be within $6 of the population mean.

This is the pvalue of Z when X = 139 + 6 = 145 subtracted by the pvalue of Z when X = 139 - 6 = 133.

X = 145

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{145 - 139}{3.464}

Z = 1.73

Z = 1.73 has a pvalue of 0.9582

X = 133

Z = \frac{X - \mu}{s}

Z = \frac{133 - 139}{3.464}

Z = -1.73

Z = -1.73 has a pvalue of 0.0418

0.9582 - 0.0418 = 0.9164

So

P (within $6 of 4) = 0.9164

4 0
3 years ago
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