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RoseWind [281]
3 years ago
9

What is the perpendicular slope of -8?

Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0

Answer:

m'=1/8

Step-by-step explanation:

m × m' = — 1

(—8) × m' = — 1

m' = 1/8

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Simplify please and show steps:<br><br> Sec (x) tan (x) csc (x) cot (x) sin (x) cos (x)
Airida [17]

Answer:

<h2>The answer is 1</h2>

Step-by-step explanation:

First of all transform the expression using trigonometric identities

That's

\sec(x)  =  \frac{1}{ \cos(x) }

\csc(x )   =  \frac{1}{ \sin(x) }

\cot(x)  =  \frac{1}{ \tan(x) }

So we have

\frac{1}{ \cos(x) }  \times  \tan(x)  \times  \frac{1}{ \sin(x) }  \times  \frac{1}{ \tan(x) }  \times  \sin(x)  \times  \cos(x)

Reduce the expression with tan x

We have

\frac{1}{ \cos(x) }   \times \cos(x)  \times  \frac{1}{ \sin(x) }  \times  \sin(x)

Reduce the expression with cos x

That's

1 \times  \frac{1}{ \sin(x) }  \times  \sin(x)

Reduce the expression with sin x

We have

1 \times 1

We have the final answer as

<h3>1</h3>

Hope this helps you

5 0
4 years ago
1/4 cup equals how many pounds?
Leno4ka [110]

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6 0
4 years ago
Which expression is equivalent to (m8n-4) 1/4
ser-zykov [4K]

Answer:

D. \dfrac{m^2}{n}

Step-by-step explanation:

I assume this is your problem:

(m^8n^{-4})^{\frac{1}{4}}

If so, then this is the solution.

(m^8n^{-4})^{\frac{1}{4}} =

= m^{8 \times \frac{1}{4}} n^{-4 \times \frac{1}{4}}

= m^2 n^{-1}

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