Question

Find the equation of a line perpendicular to x=6+6y that passes through the point (-8,6)

Answer 1

Answer:

y = -6x - 42

Step-by-step explanation:

First solve for y in x = 6 + 6y.

6y + 6 = x

6y = x - 6

6/6y = x/6 - 6/6

y = 1/6x - 1    the slope is 1/6.  

Perpendicular lines slopes are negative reciprocals of each other.

So the new equation will have the slope of -6 ( the negative reciprocal of 1/6)

Next solve for "b" by  using y = mx + b and the new slope of -6 and the point (-8,6)

y = mx + b

6 = -6(-8) + b

6 = 48 + b

-42 = b

The equation of the line is y = -6x - 42