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posledela
2 years ago
15

Find the equation of a line perpendicular to x=6+6y that passes through the point (-8,6)

Mathematics
1 answer:
alexgriva [62]2 years ago
8 0

Answer:

y = -6x - 42

Step-by-step explanation:

First solve for y in x = 6 + 6y.

6y + 6 = x

6y = x - 6

6/6y = x/6 - 6/6

y = 1/6x - 1    the slope is 1/6.  

Perpendicular lines slopes are negative reciprocals of each other.

So the new equation will have the slope of -6 ( the negative reciprocal of 1/6)

Next solve for "b" by  using y = mx + b and the new slope of -6 and the point (-8,6)

y = mx + b

6 = -6(-8) + b

6 = 48 + b

-42 = b

The equation of the line is y = -6x - 42

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The length around the outside of semicircle O from point L through point M to point N is 14 centimeters. The perimeter of semici
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3 years ago
Helping others makes a person good ​
oksano4ka [1.4K]

Answer:

9 cm.

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Let the height of the pyramid be h cm, then the height of the cuboid is (15 - h) cm.

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= hs^2/3 cm^3

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2 years ago
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Step-by-step explanation:

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I hope this helps!

6 0
2 years ago
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