Number of people < (should be smaller than or equal to but I don't have that button on my keyboard) (100-7) / 15.50
103/15.50 = 6.64516...
You can't have .645 of a person, so you must round down. Therefore, she can bring 6 people including herself.
<span>Winning Probablity = 0.2, hence Losing Probability = 0.8
Probablity of winning atmost one time, that means win one and lose four times or lose all the times. So p(W1 or W0) = p (W1) + p(W0)
Winning once W1 is equal to L4, winning zero times is losing 5 times.
p(W1) = p(W1&L4) and this happens 5 times; p(W0) = p(L5);
p (W1) + p(W0) = p(L4) + p(L5)
p(L4) + p(L5) = (5 x 0.2 x 0.8^4) + (0.8^5) => 0.8^4 + 0.8^5
p(W1 or W0) = 0.4096 + 0.32768 = 0.7373</span>
Answer:
you need to first figure out the equation f.
it says that 18=2/5f, so why don't we use inverse operation and multiply 18 by 5/2. and the answer would be....
Step-by-step explanation:
Using it's concept, it is found that the relative frequency probability of rolling an even number based on this experiment is 
.
A relative frequency is the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem:
- 50 dices are thrown, hence
. - 22 resulted in an even number, hence
The <u>relative frequency</u> is given by:
A similar problem is given at brainly.com/question/20630951
