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2 years ago

When the points are in the SAME quadrant, what operation do you do to find the distance between them?

Mathematics

1 answer:

Mademuasel [1]2 years ago

8 0

Use this formula, it’s called distance formula

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Write an Equivalent Expression by combining like terms for 2x+3x+y+2y

Vlada [557]

Answer:

5x+3y

Step-by-step explanation:

2x+3x=5x since they have the same variable.

y+2y

1y+2y u can put a 1 so that would be 3y

5x+3y

4 0

3 years ago

the height of an airplane as it descends to an airport runway is it rational ,integers, whole ,or irrational?

mario62 [17]

Rational. Not whole or integer because its an exact measurement and not irrational because it CAN be expressed as a ratio (fraction, decimal measurement )

6 0

3 years ago

How to type a line above the number 6 on chromebook.

hjlf

Answer:

you put in the number 6 but you leave room uptop so enter and then put 6 for the----- so in other words

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8 0

2 years ago

You are researching two glaciers.the first glacier flows at a rate of 75 meters in 3 days.the second glacier flows at a rate of

podryga [215]

Answer:

$1.3\ days$

Step-by-step explanation:

step 1

Find the units rate of the first glacier

$\frac{75}{3}=25\frac{meters}{day}$

using proportion

$\frac{25}{1}\frac{meters}{day}=\frac{200}{x}\frac{meters}{days}\\ \\x=200/25\\ \\x=8\ days$

step 2

Find the units rate of the second glacier

$\frac{107.5}{5}=21.5\frac{meters}{day}$

using proportion

$\frac{21.5}{1}\frac{meters}{day}=\frac{200}{x}\frac{meters}{days}\\ \\x=200/21.5\\ \\x=9.3\ days$

step 3

Find the difference

$9.3\ days-8\ days=1.3\ days$

4 0

2 years ago

8) through: (-3, -2), perp. to y = x – 1 A) y=-5x – 1 B) y=-4x – 5 C) y=-x – 5 D) y=-5x – 4

nexus9112 [7]

Answer:

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

Solution:

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1$

We know that, product of slopes of perpendicular lines is -1.

So, 1 $\times$ slope of perpendicular line = -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

$\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)$

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

8 0

3 years ago