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mamaluj [8]
3 years ago
10

When the points are in the SAME quadrant, what operation do you do to find the distance between them?

Mathematics
1 answer:
Mademuasel [1]3 years ago
8 0
Use this formula, it’s called distance formula

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Which equation could represent a circle with a center located at (11,-5)
Anon25 [30]
The standard equation of a circle is:

(x-h)^2-(y-k)^2=r^2 where (h,k) is the center and r is the radius.

We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.


(x-h)^2-(y-k)^2=r^2 \\ (11,-5)=(h,k) \\ (x-11)^2-(y-5)^2=64

The bolded part is your answer. Since the radius is not given, we can put any value.

6 0
3 years ago
What is the value of p+q
Korvikt [17]

ax^2+bx+c=0\\\\x_1,\ x_2-solutions\\\\x_1+x_2=\dfrac{-b}{a}\\--------------------------\\\\4x^2-7x-2=0\\\\a=4,\ b=-7,\ c=-2\\\\p,\ q-solutions\\\\p+q=\dfrac{-(-7)}{4}=\dfrac{7}{4}

6 0
3 years ago
Use the rules to evaluate or simplify. Write without negative exponents.
zhannawk [14.2K]
(y^-5) / (y^-2)
Flip fraction and get rid of the negative from the exponents (you can do that!)
(y^2) / (y^5)
(y * y) / (y * y * y * y * y)
Cancel y's
1 / (y * y * y)
1 / (y^3)

That's your answer.
Have an awesome day! :)
7 0
3 years ago
Two groups of students were asked how far they lived from their school. The table shows the distances in miles: Group A (distanc
iogann1982 [59]

The mean is equal for Group A and Group B.

<h2>Given </h2>

Two groups of students were asked how far they lived from their school.

The table shows the distances in miles:

Group A (distance in miles) 1 1.5 3.03 3.2 2.8 1.5 1.8 2.5 2.2

Group B (distance in miles) 2 2.5 3.23 1.3 1.8 2.4 3 1.5 1.8

<h3>What is mean?</h3>

The mean of any data set or observation is equal to the sum of all the observations and divided by the number of observations.

The formula used to calculate the mean is;

\rm Mean  = \dfrac{Sum \ of \ all \ observation}{Number \ of \ obrservation}

The mean of group A is;

\rm Mean  = \dfrac{Sum \ of \ all \ observation}{Number \ of \ obrservation}\\\\\rm GroupA \ mean = \dfrac{1 + 1.5 + 3.03 + 3.2 + 2.8 + 1.5 + 1.8 + 2.5 + 2.2}{9 }\\\\\rm Group A \ mean=\dfrac{ 19.53}{9}\\\\ Group A \ mean = 2.17

The mean of group B is;

\rm Mean  = \dfrac{Sum \ of \ all \ observation}{Number \ of \ obrservation}\\\\\rm Group B \ mean = \dfrac{2 + 2.5 + 3.23 + 1.3 + 1.8 + 2.4 + 3 + 1.5 + 1.8}{9} \\\\Group B \ mean = \dfrac{19.53}{9}\\\\ Group B \ mean = 2.17

Hence, the mean is equal for Group A and Group B.

To know more about Mean click the link given below.

brainly.com/question/12513463

7 0
2 years ago
-
insens350 [35]

Answer:

If my cousin gave me $16 ( my real cousins never did T_T) and I am left with $8 while buying a present. The present cost $8...

Wow, I thought I was bad at math

5 0
2 years ago
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