Hi there there's several ways this could be proven one way us to consider the allied angle theory where two angles formed between parallel lines are supplementary which in this case can be proven by
2(45)+90=180⁰ ✔
or 3(45)+45=180⁰✔
this would not be the case if it wasn't parallel
Consequently, you can also use the alternate angle theory where you essentially extend one of the lines and you'll see two equal alternate angles
An=a1(r)^(n-1)
a1=first term
r=common rati
common ratio is a term divded by previous term
6/3=2
r=2
first term is 3
an=3(2)^(n-1)
14th term
a14=3(2)^(14-1)
a14=3(2)^13
a14=3(8192)
a14=24576
the 14th term is 24576
Answer:
43.75 or simplified as 43 3/4 which is a mixed number
Step-by-step explanation:
How I did it is divide 5 and 8 and got 0.625 and I divided 70 by 0.625 and got 43.75 and I simplified it as a maxed number and got 43 3/4
If your teacher is asking "which of the following can be used to prove the triangles congruent?" then I agree with your statement that it's "none of the above". We simply don't have enough information to determine if the triangles are congruent or not. If we wanted to use SAS, then we'd have to know if EB = BD was true. If we wanted ASA, then we'd have to know that A = C. If we wanted AAS, then we'd have to know that E = D.
In short, you have the correct answer. Nice work.
= 6.7082