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daser333 [38]
3 years ago
15

What is a point-slope equation of the line with slope - 10 that goes through the point (1.4) Ay- 4 = -10(x - 1) By+43-10(x+1) O

c. y - 4 = 10(x-1) D. + 4 = 10(x+1)​
Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

Answer:

y-4=-10(x-1)

Step-by-step explanation:

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Hi I need help please ASAP
Slav-nsk [51]
Get photomath or Symbolab!!!
6 0
3 years ago
A triangular pyramid has a base with an area of 43 cm squared and lateral faces with bases of 10 cm and heights of 8.6 cm. What
Jet001 [13]

Answer:

The total surface area of triangular pyramid is 172 cm squared

Step-by-step explanation:

Triangular pyramid:

  • Number of faces 4.
  • Number of vertices of a triangular pyramid is 6.
  • The volume  is \frac13 AH. A= area of the pyramid's base and H= height of the pyramid.
  • The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.

Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.

The 3 sides of the triangular pyramid is triangle in shape.

The area of triangle is \frac12 \times base \times height.

The lateral surface area of the triangular pyramid is

=3(\frac12 \times base \times height)

=3(\frac12\times 10\times8.6) cm squared

=129 cm squared

The total surface area of triangular pyramid is

=Area of the base + lateral surface area

=(43+129) cm squared

=172  cm squared

8 0
4 years ago
Robin was just hired at Groceries & More as a cashier. She is paid $9 an hour. She works 30 hours a week and is going to sav
Tpy6a [65]

Answer:

5 weeks

Step-by-step explanation:

$ 9 an hr for 30 hrs.....(9 * 30) = $270

they deduct $ 27 from her weekly check

so she clears (270 - 27) = $ 243 per week

she wants to get to $ 1200...

1200 / 243 = 4.94 weeks......we are gonna have to round up to 5 weeks because 4 weeks is just a little short.

6 0
4 years ago
If a= -5 and b= -2,then what is the value of [a-b]2
Anvisha [2.4K]
Substitute= -5–2 x 2
solve= 10x2
=20
5 0
3 years ago
Read 2 more answers
I need help for this, thanks
gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

---------------------------------------------------------------------------------------

(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

5 0
3 years ago
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