Third term = t3 = ar^2 = 444 eq. (1)
Seventh term = t7 = ar^6 = 7104 eq. (2)
By solving (1) and (2) we get,
ar^2 = 444
=> a = 444 / r^2 eq. (3)
And ar^6 = 7104
(444/r^2)r^6 = 7104
444 r^4 = 7104
r^4 = 7104/444
= 16
r2 = 4
r = 2
Substitute r value in (3)
a = 444 / r^2
= 444 / 2^2
= 444 / 4
= 111
Therefore a = 111 and r = 2
Therefore t6 = ar^5
= 111(2)^5
= 111(32)
= 3552.
<span>Therefore the 6th term in the geometric series is 3552.</span>
Equilateral triangle. because all sides are equal.
The first four terms of the sequence are 3 , 6 , 12 , 24
Step-by-step explanation:
We need to find the first four terms of the sequence 
where
to find them do that
- Substitute n by 2 in the rule to find

- Substitute n by 3 in the rule to find

- Substitute n by 4 in the rule to find

∵ 
- Substitute n by 2 to find the 2nd term
∴ 
∴ 
∵ 
∴ 
∴ 
- Substitute n by 3 to find the 3rd term
∴ 
∴ 
∵ 
∴ 
∴ 
- Substitute n by 4 to find the 4th term
∴ 
∴ 
∵ 
∴ 
∴ 
The first four terms of the sequence are 3 , 6 , 12 , 24
Learn more:
You can learn more about the sequences in brainly.com/question/1522572
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Answer: 4(5j+7) = 20j+28
Step-by-step explanation: