All categories

4 years ago

Can you help me solve this?

2 answers:

6 0

Not possible, because it would come out as 4=-2 and that isn't possible

5 0

2y + 4 = 2(y - 1)

2y + 4 = 2y - 2

4 = -2

Since 4 = -2 is false, there is no solution.

Hope this helped :)

You might be interested in

Mila [183]

X= 49750
Hope this helps! :)

5 0

3 years ago

konstantin123 [22]

B and c because i get it because I have magic powersssss

3 0

3 years ago

laila [671]

It's a quadratic equation in disguise. If you let $y=x^{-1}$ , then $y^2=x^{-2}$ , and we can rewrite the equation as

$5y^2-17y+6=0$

Solve for $y$ however you like; we get $y=\dfrac25$ and $y=3$ .

But we want to solve for $x$ , so we have

$y=x^{-1}=\dfrac25\implies x=\dfrac52$

$y=x^{-1}=3\implies x=\dfrac13$

5 0

4 years ago

BartSMP [9]

24.948 kilograms hope this helps

7 0

3 years ago

aleksley [76]

Answer:

A = x^2 + 5x - 14

Step-by-step explanation:

A = L × W

A = (x+7) × (x-2)

A = x^2 + 7x - 2x - 14

5 0

4 years ago