Answer:
D. is used to reveal an underlying pattern in the data.
Step-by-step explanation:
Smoothing a time series is achieved when a computer uses some pre-programmed calculation methods to remove noise from large volumes of data. Smoothing helps a user detect patterns in a set of data, thus making it possible to make future predictions. For example, smoothing can be used in the prediction of the rise and fall of stock prices. This helps the traders to have an idea of what to expect in the cost of trading.
Although smoothing reveals the patterns in a set of data, it provides no explanation as to why it is so. It is left to the researcher to draw conclusions as to the reasons for the patterns.
Answer:
<h2>
88859.375 & f(n)= 28000(0.75)×</h2>
Step-by-step explanation:
using the information on the problem a function can can be made
f(n)= 28000(0.75)×
where x is the amount of years
plug in 4 for x in the equation to get
f(4)=8859.375
1. Place your compass point on X and measure the distance to point Y. Swing an arc of this size above (or below) the segment.
2. Without changing the span on the compass, place the compass point on Y and swing the same arc, intersecting with the first arc.
3. Label the point of intersection as the third vertex of the equilateral triangle.
4. Use you straight edge and connect the points.
Answer:
The statement If ∠A ≅ ∠C not prove that Δ ABD ≅ Δ CBD by SAS ⇒ C
Step-by-step explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse
leg of the 2nd right angle Δ
* Lets solve the problem
- In the 2 triangles ABD , CBD
∵ AB = CB
∵ BD is a common side in the two triangles
- If AD = CD
∴ Δ ABD ≅ Δ CBD ⇒ SSS
- If BD bisects ∠ABC
∴ m∠ABD = m∠CBD
∴ Δ ABD ≅ Δ CBD ⇒ SAS
- If ∠A = ∠C
∴ Δ ABD not congruent to Δ CBD by SAS because ∠A and ∠C
not included between the congruent sides
* The statement If ∠A ≅ ∠C not prove that Δ ABD ≅ Δ CBD by SAS