Your answer is 104 square inches because you have to find the area of the top rectangle by multiplying 12 x 7, then find the area of the bottom square by multiplying 5 x 4, and then add both answers together which equals 104 square centimeters ;)
What is the interquartile range of the data set? {48, 50, 65, 60, 80, 42, 45, 50, 42, 55, 45}
MissTica
Order the number:
42,42,45,45,48,50,50,55,60,65,80
Mean:50
Quartile 1:45
Quartile 3:60
60-45=15. As a result, the interquartile range is 15. Hope it help!
My answer -
<span>1. Use symbols (not words) to express quotient
2. Use exponent symbol (^) to denote exponents
3. Just write out question number, question, and choices. No need for
extra information (such as points). Also, don't leave blank lines
between choices. This extraneous that we don't need just makes your
whole question very very long, and means a lot of scrolling on our part.
4. You should only post 2 or 3 questions at a time.
1) (6x^3 − 18x^2 − 12x) / (−6x) = −x^2 + 3x + 2 ----> so much simpler to read !
2) (d^7 g^13) / (d^2 g^7) = d^(7−2) g^(13−7) = d^5 g^6 ----> much easier to read !
3) (4x − 6)^2 = 16x^2 − 24x − 24x + 36 = 16x^2 − 48x + 36
4) (x^2 / y^5)^4 = (x^2)^4 / (y^5)^4 = x^8 / y^20
5) (3x + 5y)(4x − 3y) = 12x^2 − 9xy + 20xy − 15y^2 = 12x^2 + 11xy − 15y^2
6) (3x^3y^4z^4)(2x^3y^4z^2) = (3*2) x^(3+3) y^(4+4) z^(4+2) = 6 x^6 y^8 z^6
7) 5x + 3x^4 − 7x^3 ----> Fourth degree trinomial
8) (5x^3 − 5x − 8) + (2x^3 + 4x + 2) = 7x^3 − x − 6
9) (x − 1) + (2x + 5) − (x + 3) = x + 1
10) (−4g^8h^5k^2)0(hk^2)^2 = 0 (anything multiplied by 0 = 0)
or.. (−4g^8h^5k^2)^0(hk^2)^2 = 1 (h^2 (k^2)^2) = h^2 k^4
Last question shows why it is so important to use proper symbols (such
as ^ to indicate exponents). Without such symbols, I could not tell if
the 0 was an actual number and part of multiplication, of if 0 was an
exponent of the expression preceding it.
P.S
Glad to help you have an AWESOME!!! day :)
</span>
V=4/3πr^3
36π=4/3πr^3
3/4(36π)=(4/3πr^3)3/4
27π=πr^3
π(27π)=r^3
27=r^3
square root
r=3
s.a=4πr^2
s.a=4π(3^2)
s.a=4π(9)
s.a=36π
Tony’s backpack can carry weight up to 22 but not more that that
If the variable n represents the total weight carried by tony
Then ; n less than or equal to (n=1+3+3b
=4+3b
Where b represents book
4+3b is less or equal to 22
3b is less or equal to 18
b is less or equal to 6
Therefore Tony’s backpack cannot carry more than 6 books
