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Lynna [10]
2 years ago
13

Given that f(x) = X + 3/2 a) Find f(2) b) Find f^-1(x) c) Find f^-1(12)

Mathematics
1 answer:
zysi [14]2 years ago
5 0
A) x+3/2
b) x/f
c) 12/f


Mark brainliest please


Hope this helps you
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MaRussiya [10]
Just divide it and you will get the answer
5 0
3 years ago
This figure is made up of a quadrilateral and a semicircle.
Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of AB is

AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}

The length of AD is

AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}

Since AB=AD, therefore ABCD is a square. The area of the of square is

A_1=a\times a=\sqrt{29}\times \sqrt{29} =29

The area of square is 29 units².

The area of a semicircle is

A_2=\frac{\pi}{2}r^2

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

r=\frac{d}{2}=\frac{\sqrt{29}}{2}

The area of the semicircle is

A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825

The area of the figure is

A=A_1+A_2=29+11.2825=40.3825\approx 40.4

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0
3 years ago
A radioactive substance decays according to the formula A=A0e^kt
Sholpan [36]
Without needing fancy formulas, we can conclude that after 10 years, half of the substance will be left.  So, we can make our own formula:
amount remaining = 1 / 2^(years/10)
So, after 5 years
amount remaining = 1 / 2^(5/10)
amount remaining = 1 / 2^(.5)
amount remaining = 1 / <span> <span> <span> 1.414213562 </span>
</span></span><span>amount remaining = 0.70711 * 20 grams
</span><span><span><span><span>amount remaining = </span>14.1421356237 grams

</span></span></span>


4 0
3 years ago
7.5 cm=__ m <br><br> A.0.0075<br> B.0.075<br> C.0.75<br> D.750
spayn [35]

Your answer is B. 0.075 m

5 0
3 years ago
Read 2 more answers
An ellipse has a center at the origin, a vertex along the major axis at (0, 17), and a focus at (0, −8). Which equation represen
Marianna [84]
We know that
<span>Since the focus and vertex are above and below each other, rather than side by side, I know that this ellipse must be taller than it is wide.
</span>Then 
a²<span> will go with the </span>y<span> part of the equation
</span>Also, since the focus is 8 <span>units below the center, then </span><span>c = 8
</span>since the vertex is 17<span> units above, then </span><span>a = 17
</span>The equation b²<span> = a</span>²<span> – c</span>²<span> gives me
</span>b²=17²-8²-----> b²=225
the equation is
y²/a²+x²/b²=1------> y²/289+x²/225=1

the answer is
y²/289+x²/225=1

see the attached figure

7 0
3 years ago
Read 2 more answers
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