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kvv77 [185]
3 years ago
12

Need help will give brainliest for quick answer!

Mathematics
1 answer:
scoray [572]3 years ago
3 0

Answer: -1 \leq c < 3

Step-by-step explanation:

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Can someone help me with this problem I really don’t know how to work it out and I’m getting frustrated please help..
11Alexandr11 [23.1K]

Answer:

  1 cake and 6 pies

Step-by-step explanation:

Let c represent the number of cakes Alice and George can make. Likewise, let p represent the number of pies.

Then the amount of flour they need (in cups) is ...

  3c + 2p . . . . cups of flour needed

And the amount of sugar needed is ...

  2c + 1.5p . . . cups of sugar needed

__

They want to use all 15 cups of flour they have, and all 11 cups of sugar, so the amounts above need to match the amounts on hand:

  3c + 2p = 15

  2c + 1.5p = 11

We can solve these equations various ways. One of my favorite is to use a graphing calculator. (See attached) It tells us that Alice and George can make 1 cake and 6 pies with the flour and sugar they have.

_____

If you want to solve these equations algebraically, there are several methods for that, too. Here, we can multiply the first one by 2/3 and subtract the result from the second one:

  (2c +1.5p) -(2/3)(3c +2p) = (11) -(2/3)(15)

  2c +3/2p -2c -4/3p = 11 -10 . . . . . eliminate parentheses

  1/6p = 1 . . . . . . . . . . . . . . . . . . . . . .collect terms

  p = 6 . . . . . . . . . . . . . . . . . . . . . . . . multiply by 6

Substituting into the first equation gives ...

  3c +2·6 = 15 . . . substitute 6 for p

  3c = 3 . . . . . . . . subtract 12

  c = 1 . . . . . . . . . . divide by 3

These values tell us Alice and George can make 1 cake and 6 pies with the flour and sugar they have.

7 0
3 years ago
Match the name of the sampling method descriptions given.
Sladkaya [172]
A. simple random
b. systematic
c. cluster
d. stratified
e.convenience
6 0
4 years ago
Find the value of b. Round your answer to the nearest tenth.
marissa [1.9K]

Answer:

Side CA = 7.8

Step-by-step explanation:

<u>Given:</u>

Acute angled \triangle ABC.

\angle B =40^\circ

AB = 10

BC = 12

We can use cosine rule here to find the side AC = b

<em>Formula for cosine rule: </em>

cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}

Where  

a is the side opposite to \angle A

b is the side opposite to \angle B

c is the side opposite to \angle C

cos 40 = \dfrac{12^{2}+10^{2}-b^{2}}{2\times 12\times 10}\\\Rightarrow cos 40 = \dfrac{144+100-b^{2}}{240}\\\Rightarrow 0.77 = \dfrac{244-b^{2}}{240}\\\Rightarrow 244-b^{2} = 0.77 \times 240\\\Rightarrow 244-b^{2} = 183.85\\\Rightarrow 244-183.85 = b^{2}\\\Rightarrow b^2 = 60.15\\\Rightarrow b = 7.76

To the nearest tenth <em>b = 7.8</em>

8 0
3 years ago
WILL GIVE BRAINLIEST AND 25 POINTS! Which of the following statements are true? Check all that apply. A. If any row of a square
sertanlavr [38]

Answer:

Option A, B and E

Step-by-step explanation:

Determinant = ad-bc

Let's look at the picture and solve all

<u><em>Option A)</em></u>

If the row ( c and d ) is zero, the determinant will be zero

=> a(0)-b(0)

=> 0-0

=> 0 (So, True)

<u><em>Option B) </em></u>

If a = b = c = d (Let's say 1), the determinant will be

=> (1)(1)-(1)(1)

=> 1-1

=> 0  (So, True)

<u><em>Option C)</em></u>

An Identity matrix is

=> \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

So , it's determinant will be

=> (1)(1)-(0)(0)

=> 1-0

=> 1  (So, False)

<u><em>Option D)</em></u>

The determinant with matrix will all positive numbers can be negative as well as positive. This is not necessary that it would be positive. (So, False)

<u><em>Option E)</em></u>

A zero matrix is

=> \left[\begin{array}{ccc}0&0\\0&0\end{array}\right]

So, it's determinant is:

=> (0)(0)-(0)(0)

=> 0-0

=> 0 (So,True)

5 0
3 years ago
Marking City is 5 inches away from Jamming City on the map. What is the
Anarel [89]

Answer:

87.5 miles

Step-by-step explanation:

If 2 inches is 35 miles then 4 inches will be 70 inches

to get the last inch all you have to do is divide the 35 in have to get 17.5

70 + 17.5 = 87.5

3 0
3 years ago
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