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3 years ago

Write an equation for the translation of y = |x|. 15.5 units down

2 answers:

andrey2020 [161]3 years ago

6 0

Than you consider the axes coordinates and try this for x=0 what mean origin so this 15,5 units down mean that y coordinate point will be -15,5 from what result that the first one choice is right sure

A. y = IxI -15,5

expeople1 [14]3 years ago

3 0

Answer:

Option A is correct

$y =|x| -15.5$

Step-by-step explanation:

Vertically down:

To translate the absolute parent function y=f(x) vertically, the new function we get;

g(x) = f(x) + k

when k < 0 , the function is vertically down

when k > 0, then the function is vertically up

Given the function:

The translation of y = |x|

To do vertically down with 15.5

Use the above definition we have;

$y =|x| -15.5$

Therefore, an equation for the translation of y = |x|, with 15.5 units down

is, $y =|x| -15.5$

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Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

$P(x \ge 60) \approx P(z > 1.34)$