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Setler79 [48]
2 years ago
11

The expression (x+3)(x+4), is equivalent to which of the following?

Mathematics
1 answer:
stich3 [128]2 years ago
8 0

Answer:

x² + 7x + 12

Step-by-step explanation:

x squared plus 7 x plus 12

pls give brainliest for the answer

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Step-by-step explanation:

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Which graph represents the solution to the given system? y = –2x + 5 and y = 3x – 2
DaniilM [7]
Y = -2x + 5        y =3x - 2
Since both equations are equal to 'y' you can set them equal to each other to solve.
-2x + 5 = 3x - 2             Subtract 3x from both sides
-5x + 5 = -2                  Subtract 5 from both sides
-5x = -7                        Divide -5 on both sides
x = 7/5
Plug 7/5 back in for x and solve for y.
y = -2(7/5) + 5
y = (-14/5) + (25/5)
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(7/5, 11/5) OR (1.4, 2.2)


4 0
3 years ago
Read 2 more answers
Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.
11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

\sqrt{11-2x}=\sqrt{x^{2}+4x+4}

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}

\sqrt{25}=\sqrt{25}

5=5 ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}

\sqrt{9}=\sqrt{9}

3=3 ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0
3 years ago
Read 2 more answers
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