Hello,
log base 9(m/(m-4))=-2
==>m/(m-4)=9^(-2)
==>81m=m-4
==>80m=-4
==>m=-1/20
1. First, you must apply the formula
for calculate the sum of the interior angles of a regular polygon, which is
shown below:
(n-2) × 180°
"n" is the number of sides of the polygon (n=5).
2. Then, the sum of the interior angles of the pentagon, is:
(5-2)x180°=540°
3. The problem says that the measure of each of the other interior angles is equal to the sum of the measures of the two acute angles and now you know that the sum of all the angles is 540°, then, you have:
α+α+2α+2α+2α=540°
8α=540°
α=540°/8
α=67.5°
4. Finally, the larger angle is:
2α=2(67.5°)=135°
5. Therefore, the answer is: 135°
You must factoring the number 192, you will get 192=2^6*3, so you have square root(2^6*3)=2^(6/2)*root(3) applying enhancing property.
Solve the exponent and you get =2^3*root(3)= 8*root(3)
Answer:
Hope i helped :)
Step-by-step explanation:
8) T-V =24
24 -6 =18
2x-18 =18
2x=0
x= 0/2
x=0
9)
*LMK
*L-K=x+3
*L-M=6x-10
*M-K= 3x-3
L-M + M-K = 6x -10 + 3x -3 = 9x -13
10 and 11)
Both lines are horizontal
both lines consist of intervals due to having 2 points on one line making it a distance between 2 points.
they are also concurrent lines because more then 3 lines pass through one point
they are also intersecting lines because they cross over each other
