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Katena32 [7]
2 years ago
6

0.36(18)+0.04x=0.12(24+x)

Mathematics
2 answers:
Zielflug [23.3K]2 years ago
7 0
X=45 would be the answer
zhuklara [117]2 years ago
3 0

Answer:

x = 45

Step-by-step explanation:

0.36(18) + 0.04x = 0.12(24 + x)

6.48 + 0.04x = 2.88 + 0.12x

0.04x - 0.12x = 2.88 - 6.48

-0.08x = -3.6

0.08x = 3.6

x = 3.6/0.08

x = 45

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The difference of 44 and the square of n into a expression
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Answer:

44-\sqrt{n}

7 0
3 years ago
Rewrite (123 + 456) + 789 using the Associative Law of Addition
adelina 88 [10]

Answer:

123 + (456 + 789)

Step-by-step explanation:

since this is an addition problem, the parenthesis don't matter, and they can be put wherever you want.

(123 + 456) + 789

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(123 + 456 + 789)

123 + (456 + 789)

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123 + (456 + 789)

5 0
3 years ago
16. A company spends $100 per day on fixed expenses such as electricity, rent, and the like. It also spends $35 per day on each
Paladinen [302]
C = Total Daily Cost
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5 0
3 years ago
Read 2 more answers
A college student Earned $6500 during summer vacation working as a waiter. The student invested Part of the money at 10% and the
Juliette [100K]

Answer:

The amount invested at 10% rate is $ 2200

Step-by-step explanation:

Given as :

The total amount earn by student = $6500

The total interest received at the end of year = $607

Let the amount invested at 10% rate = $x

So, The amount invested at 9% rate = ($6500 - $x)

Let the time for which money invested = 1 year

<u>Now from Simple Interest method :</u>

SI = \frac{principal\times Rate\times Time}{100}

Or, SI_1 + SI_2 = \frac{x\times 10\times 1}{100} + \frac{(6500-x)l\times 9\times 1}{100}

Or, SI_1 + SI_2 = (\frac{10x}{100})+\frac{(6500-x)\times 9}{100}

Or, $607 × 100 = 10x + (6500-x) × 9

Or, $60700 = 10x- 9x + 58500

Or, $60700 - $58500 = x

Or , 2200 = x

∴ x = 2200

So, The amount invested at 10% rate = $x = $ 2200

Hence The amount invested at 10% rate is $ 2200   Answer

5 0
3 years ago
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