In general, the average rate of change of f (x) on the interval a, b is given by f(b) – f(a) / b – a. The average rate of alteration of a function, f (x) on an interval is well-defined to be the variance of the function values at the endpoints of the interim divided by the difference in the x values at the endpoints of the interval. this is also known as the difference quotient that tells how on average, the y values of a function are changing in connection to variations in the x values. A positive or negative rate of change is applicable which match up to an increase or decrease in the y value among the two data points. It is called zero rate of change when a quantity does not change over time.
Answer:
60$ (b)
Step-by-step explanation:
we know that 20% of the total is peters - and peter has 12 dollars. We know that 20% 5 times gets us to 100%. So we multiply 12 by 5 to get a total answer of 60$
<u>Answer:</u>
Amount collected in 2012 = 3.49
and in 2013 = 3.35
<u>Explanation:</u>
Let x be the baggage fees collected in 2013 and
y be the baggage fees collected by airlines in 2012
From the given question we can obtain two equations as follows:
x + y = 6.84 $ - eq 1
and
y = 0.14 + x
as fees in 2012 exceeds that in 2013 by 0.14$
Now, solving these two equations by substitution,
we substitute y = 0.14 + x in eq 1
and solve for x,
which gives us x = 3.35 and
substituting this value in eq 1
we get y = 3.49
For this case we have a function of the form:

Where,
A: initial population of bacteria
b: growth rate
x: number of hours
Since the diameter is double every hour, then:

We must now look for the value of A.
To do this, we evaluate an ordered pair of the graph:
For (1, 2):

Clearing A we have:


Then, the function is given by:

For after 9 hours we have:

Answer:
the diameter of the bacteria after 9 hours is:

Answer:
x = 250
y = 125
u(x,y) = 3125500
Step-by-step explanation:
As given,
The utility function u(x, y) = 100xy + x + 2y
= 2 ,
= 4
Now,
Budget constraint -
x +
y = 1000
⇒2x + 4y = 1000
So,
Let v(x, y) = 2x + 4y - 1000
Now,
By Lagrange Multiplier
Δu = Δv
⇒< 100y + 1, 100x + 2 > = < 2, 4 >
By comparing, e get
100y + 1 = 2 ........(1)
100x + 2 = 4 .........(2)
Divide equation (2) to equation (1) , we get

⇒2(100y+1) = 1(100x+2)
⇒200y + 2 = 100x + 2
⇒200y = 100x
⇒2y = x
Now,
As 2x + 4y = 1000
⇒2x + 2(2y) = 1000
⇒2x + 2x = 1000
⇒4x = 1000
⇒x = 250
Now,
As 2y = x
⇒2y = 250
⇒y =
= 125
∴ we get
x = 250
y = 125
Now,
u(250, 125) = 100(250)(125) + 250 + 2(125)
= 3125000 + 250 + 250
= 3125000 + 500
= 3125500
⇒u(250, 125) = 3125500