2 years ago

Solve.

Mathematics

1 answer:

MA_775_DIABLO [31]2 years ago

3 0

Answer:

what are you asking?

Step-by-step explanation:

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The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by

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The answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

$35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\$

suppose $x = m.\frac{\pi}{6}+55$ and $\frac{\pi}{2} = 90$ degree

We know, cos(x+90°) = - sin(X)

⇒ $cos((m.\frac{\pi}{6})+55+90degree)$ degree = - $sin((m.\frac{\pi}{6})+55)$

⇒ t = $sin((m.\frac{\pi}{6})+55)$

Hence the answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

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