<span> 3a^3+8a-6
+4a^2-9a+11
=3a^3+4a^2-a+5
</span>
Answer:
let c is a point between a and b we can find the coordinates of c by using mid-point formula
the coordinate x of c is equal to
x=(x1+x2)÷2
x=(3+27)÷2
x=30÷2
x=15
the coordinate y of c is equal to
y=(y1+y2)÷2
y=(2+30)÷2
y=32÷2
y=16
so the coordinates of c are (15,16)
Answer:
Coordinates of Vertices of triangle ABC are A (-4,3) , B(4,4) and C(1,1).
As, DO is Dilation of Δ ABC by Scale factor of
.
Vertices of A' B'C' are

So, Image Δ A'B'C' will be smaller than the Pre image Δ ABC.
The two triangles will be congruent.
AO is Dilated by a factor of half , so A'O' will be half of AO.
So, correct Statements are
1. AB is parallel to A'B'.
2.DO,1/2(x, y) =
The distance from A' to the origin is half the distance from A to the origin.
The disstance between -125 and 78 is 47
Answer:
8 x 10^14 is 800000000000000, and 2 x 10^9 is 2000000000 so 8 x 10^4 is 400000 greater, Good Luck!
Step-by-step explanation: