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yarga [219]
2 years ago
11

On Saturday morning, Ahmed decided to take a bike ride from one end of the 15-mile bike trail to the other end of the bike trail

and back. His average speed the first half of the ride was 2 mph faster than his speed on the second half. Find an expression for Ahmed's total travel time. If his average speed for the first half of the ride was 12 mph, how long was Ahmed's bike ride? ​
Mathematics
1 answer:
frosja888 [35]2 years ago
3 0

The expression which relates the total time taken and the time taken for the trip is [15s + 15(s+2)] / s² + 2s and 2.32 hours respectively.

<em>Travel time = distance ÷ speed </em>

<u>Second half of the trip</u> :

  • <em>Speed = s mph</em>

  • <em>Distance covered = 15 miles</em>

<u>Time taken for second half of trip</u> :

Time taken = 15 / s

<u>First half of the trip</u> :

  • <em>Speed = s + 2 mph </em>

<u>Time taken for first half of trip :</u>

Time taken = 15 / (s+2)

<u>Total time taken :</u>

<em>First half + second half</em>

15/(s+2) + 15/s = [15s + 15(s+2)] / s² + 2s

B)

If s = 12

<em>Substitute s = 12 into the expression</em> :

[15(12) + 15(12+2)] / 12² + 2(12)

[180 + 210] / 144 + 24

390 / 168

= 2.32 hours

Therefore, the total time taken is 2.32 hours.

Learn more : brainly.com/question/18796573

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