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3 years ago

What is the area of the kite?

Mathematics

1 answer:

finlep [7]3 years ago

3 0

Answer:

Step-by-step explanation:

area of kite=product of diagonals ÷2=(30×4)÷2=120/2=60 ft²

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Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui

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<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

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Substituting the value of H in (1), we get:

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Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

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L = 15.874 cm

B = 15.874 cm

H = 7.8937 cm

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