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3 years ago

What is 1/3 times 1/3 times 1/3

Mathematics

2 answers:

s344n2d4d5 [400]3 years ago

6 0

Answer:

1/3 cubed is 1/27

Step-by-step explanation:

1/3*1/3*1/3 is equal to 1/27

e-lub [12.9K]3 years ago

4 0

Answer:

1/27

Step-by-step explanation:

since the numerator is only one, just go ahead and write one on the numerator spot. Then you multiply the bottom 3^3 is 27, therefore you get 1/27th

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Suppose a math class has 18 females (2 of whom speak French) and 13 males (5 of whom speak French).

alisha [4.7K]

18 females, 13 males, total: 31 students.

•female french students: 2

•male french students: 5

probability: male french = 5/31,

total students

edit: as a percentage, 16.129 %

6 0

2 years ago

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

2 years ago

Find the ratio in the simplest form 15 minutes to 2 hours

Lelu [443]

15min:2h
15min:120min
15/120
3/24
1:8 is the answer

3 0

3 years ago

Write the equation of the line with the given slope and y- intercept. 1.Slope is -2 and a y-intercept of 5.

Monica [59]

Since the slope is -2, then m=-2. Since the y-intercept is 5, b=5. Then, we can create the equation: y=-2x+5

Since the slope is $\frac{3}{4}$ , then m= $\frac{3}{4}$ . Since the y-intercept is -3, b=-3.

Then, we can create the equation: y= $\frac{3}{4}$ x-3

5 0

2 years ago

What is the solution of the equation x − 2 = 29? -31 -27 27 31

Allisa [31]

31-2=29 you add 2 to both sides so -2 cancels and you are left with X=31

the answer is 31

5 0

3 years ago