Answer:
m ≠1 ( all m in R except 1 )
Step-by-step explanation:
hello :
mx − y + 3 = 0.....(*)
(2m − 1)x − y + 4 = 0 ....(**)
multiply (*) by : -1 you have : -mx+y-3=0 ....(***)
(2m − 1)x − y + 4 = 0 ....(**)
add(***) and(**) : -mx+ (2m − 1)x+1 =0
(2m-m-1)x+1=0
(m-1)x = -1
this system have no solution if : m-1≠0 means : m ≠1
Answer:
C. -4x - 1
Step-by-step explanation:
Distribute the term outside of the parenthesis, Multiply each term in the parenthesis by the term outside (do not forget to include the negative sign when multiplying);
Simplify,
It's not specified whether 1 is the 1st or 2nd roll: HOWER:
The 1st Roll is "1": P(odd sum/the 1st Roll is 1)
What is the sample space of all numbers starting with "1":
{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),} = 6
the couple of add sum=(1,2), (1,4), (1,6), =3
P(odd sum/ 1st is 1) = 3/6 =1/2
or in applying the formula:
P(odd sum/the 1st Roll is 1) =P(odd sum ∩ 1) / P(getting "1") it will give the same probability = 1/2
NOW if the 2nd Roll is "1", it 's still 1/2
Answer: Hello!.......
1e-12 I am SOOO sorry if im wrong. I'm So sorry. Hope this helps you.♥
Step-by-step explanation:
Mark me brainest please. Hope I helped! Hope you make an 100%
-Anna♥
Answer:
$(400+80x)
Step-by-step explanation:
We are required to find the total income on Friday Night
Ticket costs $5 each and they sold 80 tickets
Total ticket Sales = 80 X $5 =$400
There was a donation of $x per ticket, so for 80 tickets, there was a donation of $80x.
Total Income on Friday Night=Ticket Sale+Donations= $(400+80x)
