All categories

3 years ago

One person is selected at random from a class of 20 males and 19 female

Mathematics

2 answers:

Mice21 [21]3 years ago

6 0

There is a higher chance that person is male by one in 39. Hope this helps!!!

eimsori [14]3 years ago

5 0

It would be very close to either, since 20 and 19 are very near, but since there are 20 males, probably male. But it could be female aswell

You might be interested in

A classmate simplified a rational expression below

lara31 [8.8K]

<h2>Part a) </h2><h2>Explain the error in this simplification.</h2>

Given the simplified expression

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

$\:1-2x-4=x^2-x-2$

$-2x-3=x^2-x-2\:\:$

$0=x^2-2x-2\:\:$

$0=\left(x-1\right)\left(x-1\right)$

$x=1$

<u><em>Identifying the Main Error</em></u>

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$ ← ERROR Starts here

<u><em>Here is the Explanation of the Error </em></u>

<u><em /></u> $\mathrm{The\:equation\:should\:have\:been\:Multiplied\:by\:LCM=}\left(x-2\right)\left(x+2\right)$ <em>. </em>In your case you wrongly multiply the equation.

<em><u>CORRECTION</u></em>

<em>HERE IS HOW YOU SHOULD HAVE MULTIPLIED BY </em><em>LCM = (x-2)(x+2):</em>

<em />

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)$

$\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

<h2>Part b) </h2><h2>Show your work as you correct the error</h2>

Here is the complete correction of the error.

Considering the expression

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}x-2,\:x+2:\quad \left(x-2\right)\left(x+2\right)$

$1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)$

$\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

$x^2-2x-8=x^2-x-2$

$x^2-2x-8+8=x^2-x-2+8$

$x^2-2x=x^2-x+6$

$-x=6$

$\frac{-x}{-1}=\frac{6}{-1}$

$x=-6$

3 0

3 years ago

How much of a 14% solution of iodine should be added to 89 ounces of a 47% iodine solution to get a 29% solution

Andrews [41]

We have 89 ounces of 47% iodine.
We will add "x" ounces of 14% iodine to get a 29% iodine solution.
89 * .47 + .14x = .29 * (89 + x)
41.83 + .14x = 25.81 + .29x
16.02 = .15x
x = 106.80
So, we must add 106.80 ounces of 14% iodine to get a 29% iodine solution.
(for a total of 195.80 ounces)

Source:
http://www.1728.org/mixture.htm

3 0

3 years ago

if a house is 20 ft high and its picture has a height of 2.3 inches and a width of 5.1 inches, how wide is the actual house?

Murljashka [212]

1 ft = 12 inches

20 ft = 240 inches

240/2.3 x 5.1 = 532 inches

532 / 12 = 44.3 ft

Actual house is 20 ft high and 44 feet wide

3 0

4 years ago

An item on sale costs 60% of the original price. If the original price was $30, what is the sale price?

jolli1 [7]

Answer: $18

Step-by-step explanation:

60% of original cost means 40% is taken off

40% = 0.4

30 x 0.4 = 12 so that is how much will be taken off

30-12= 18

$18

8 0

3 years ago

Decrease £843 by 91% rounded to 2 DP

34kurt

Answer:

Percent (%)' means 'out of one hundred':

p% = p 'out of one hundred',

p% is read p 'percent',

p% = p/100 = p ÷ 100.

91% = 91/100 = 91 ÷ 100 = 0.91.

100% = 100/100 = 100 ÷ 100 = 1.

Decrease number by 91% of its value.

Percentage decrease = 91% × 843

New value = 843 - Percentage decrease

Calculate the New Value

New value =

843 - Percentage decrease =

843 - (91% × 843) =

843 - 91% × 843 =

(1 - 91%) × 843 =

(100% - 91%) × 843 =

9% × 843 =

9 ÷ 100 × 843 =

9 × 843 ÷ 100 =

7,587 ÷ 100 =

75.87

Calculate absolute change (actual difference)

Absolute change (actual difference) =

New value - 843 =

75.87 - 843 =

- 767.13

Proof.

Calculate percentage decrease:

Percentage decrease =

91% × 843 =

91 ÷ 100 × 843 =

91 × 843 ÷ 100 =

76,713 ÷ 100 =

767.13

Step-by-step explanation:

Hope it is helpful....

6 0

3 years ago